A. 1/5 fish
We know that 2/5 of Mike's fish are clownfish. Therefore, 3/5 are not clownish as 5/5 – 2/5 = 3/5. Also, if you look at the model, there are five pieces. If we assume that model represents the whole of Mike's fish and you take away two pieces, you are left with 3/5. So we know that the remaining fish is 3/5
Next, we know that of these 3/5 fish, 1/3 is damselfish, so we need to find 1/3 of 3/5. To do this, we must multiply 1/3 by 3/5 as "of" means multiply in Math.
So: 1/3 • 3/5 = 1 • 3/3 • 5 = 3/15 3 ÷ 3 = 1 and 15 ÷ 3 = 5 3/15 = 1/5
1/5 of Mike's fish are damsel fish
B. 2/5 fish
Now we know that 1/5 of Mike's fish is damselfish, and 2/5 is clownfish. To find the fraction of his fish that are neither, therefore, we must subtract their sum from the whole.
First, we add 1/5 and 2/5 together. Adding the numerators, 1 and 2, we get 1/5 + 2/5 = 3/5
Next, we subtract: 5/5 – 3/5 = 2/5, so 2/5 of his fish are neither clownfish or damselfish
And if you look at the model again, you can see that if you cross out 1 piece for the damselfish, and 2 pieces for the clownfish, you are left with 2/5
Good luck to you! I finally figured it out. XD it took a while. I didn’t recall the algebraic approach, if any.
To get the difference between the two years you have to take the numbers away from eachother.
So in this case, 400,000-276,650= 123,350
This means that this year the farmer planted 123,350 more corn stalks this year compared to last year.
Answer:
y= -5x-5
Step-by-step explanation:
because m=y2-y1/x2-x1 and then you plug in one of the point to find the y intercept or b and the answer you should get is -5 for be so it ends up being y= -5x-5
Im guessing that your teacher wants you to apply the fact that no matter what order your numbers are in when adding or multiplying your outcome will be the same. So one multiplication fact is 16*147=2352 . Also if you multiply a negative times a negative you will get a positive number so -147*-16=2352 .
I hope this helps a lil:)