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marin [14]
3 years ago
6

Find the perimeter of a rectangle that has a length of 2x +7 and a width of 5x.

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
6 0

Answer:

14x + 14

Step-by-step explanation:

perimeter formula: 2(w+l)

2(2x+7+5x) = 2(7x+7) = 14x+14

Harlamova29_29 [7]3 years ago
3 0

Answer:

14x + 14

Step-by-step explanation:

Perimeter = 2( L + W)

2(2x+7 + 5x) = 2(7x + 7)

distributive property

= 14x + 14

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Tess has 42 words of an essay typed and is typing about 1.3 words per second. Margo 122 words of an essay typed and is erasing a
scoray [572]

Answer:

  32 seconds

Step-by-step explanation:

For some number of seconds (s), Tess's essay length (t) will be ...

  t = 42 +1.3s

and Margo's essay length (m) will be ...

  m = 122 -1.2s

We will have t > m when ...

  t > m

  42 +1.3s > 122 -1.2s

  2.5s > 80 . . . . . . . . add 1.2s-42

  s > 32 . . . . . . . . . . . divide by 2.5

After 32 seconds, Tess's essay will exceed Margo's in length.

 

6 0
3 years ago
A doctor has an annual income of $152,125. The income tax that doctor has to pay is 6%. What is the amount of income tax in doll
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9514 1404 393

Answer:

  $9,127.50

Step-by-step explanation:

6% of $152,125 is ...

  0.06 × $152,125 = $9,127.50

The doctor has to pay $9,127.50 in income tax.

4 0
3 years ago
Mr. Golv is practicing his jiu jitsu drill where he does 5 guard passes and 2 kimura arm locks. A guard pass takes G seconds, an
agasfer [191]
1.)C
2.)A
3.)B
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4 0
3 years ago
Read 2 more answers
The accompanying data represent the daily​ (for example, Monday to​ Tuesday) movement of Johnson​ & Johnson​ (JNJ) stock for
egoroff_w [7]

Supposing that the stock increases in 37 days, the 95% confidence interval for the proportion of days JMJ stock increases is: (0.484, 0.7292)

  • The lower bound is of 0.484.
  • The upper bound is of 0.7292.
  • The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

Supposing that it increases on 37 out of 61 days:

n = 61, \pi = \frac{37}{61} = 0.6066

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 - 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.484

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 + 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.7292

The ​95% confidence interval for the proportion of days JMJ stock increases is (0.484, 0.7292), in which 0.484 is the lower bound and 0.7292 is the upper bound.

The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

A similar problem is given at brainly.com/question/16807970

4 0
3 years ago
Find the equation of the line which passes through the point (7,2) and is perpendicular to y=5x-2
MariettaO [177]

Answer:

\displaystyle y=-\frac{1}{5}x+\frac{17}{5}

Step-by-step explanation:

<u>Equation of a line</u>

A line can be represented by an equation of the form

y=mx+b

Where x is the independent variable, m is the slope of the line, b is the y-intercept and y is the dependent variable.

We need to find the equation of the line passing through the point (7,2) and is perpendicular to the line y=5x-2.

Two lines with slopes m1 and m2 are perpendicular if:

m_1.m_2=-1

The given line has a slope m1=5, thus the slope of our required line is:

\displaystyle m_2=-\frac{1}{m_1}=-\frac{1}{5}

The equation of the line now can be expressed as:

\displaystyle y=-\frac{1}{5}x+b

We need to find the value of b, which can be done by using the point (7,2):

\displaystyle 2=-\frac{1}{5}*7+b

Operating:

\displaystyle 2=-\frac{7}{5}+b

Multiplying by 5:

10=-7+5b

Operating:

10+7=5b

Solving for b:

\displaystyle b=\frac{17}{5}

The equation of the line is:

\boxed{\displaystyle y=-\frac{1}{5}x+\frac{17}{5}}

7 0
3 years ago
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