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omeli [17]
3 years ago
6

Help me really quick!!!

Mathematics
1 answer:
aleksandrvk [35]3 years ago
3 0
The answer is 26. I'm assuming you don't need work.
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Solve for x.<br> 13<br> =(5x+ 6)/8 + <br> (5x+4)/4
valkas [14]

Answer: x=6

Step-by-step explanation:

To solve for x, we want to isolate the variable.

\frac{5x+6}{8} +\frac{5x+4}{4} =13        [get common denominator]

\frac{5x+6}{8} +\frac{2(5x+4)}{8} =13     [add fractions]

\frac{5x+6+10x+8}{y} =13          [combine like terms]

\frac{15x+14}{8} =13                 [multiply both sides by 8]

15x+14=104            [subtract both sides by 14]

15x=90\\                      [divide both sides by 15]

x=6

Now, we know that x=6.

3 0
3 years ago
Which statement correctly compares the values in the statement?
andrezito [222]

Answer:

All of the answers

Step-by-step explanation:

It is what it is

4 0
3 years ago
Find the area of a square with a side of 20 cm
Bezzdna [24]

Answer:

80 cm

Step-by-step explanation:

This is because the shape is a square, and area is width x height x length.

Since the shape is a square, all sides are the same therefore the answer is 80 cm.

5 0
3 years ago
Read 2 more answers
ABCD is a quadrilateral. Three of the angles of ABCD measure 100°, 87, and 106°, respectively. Find the measure of the
ladessa [460]

Answer:

A

Step-by-step explanation:

The angles in a quadrilateral add up to 360 degrees.

100 + 87 + 106= 293

360 - 293 = 67

8 0
3 years ago
Read 2 more answers
The graph of $y=ax^2+bx+c$ passes through points $(0,5)$, $(1,10)$, and $(2,19)$. Find $a+b+c$.
MAVERICK [17]

Answer:

a+b+c=10

Step-by-step explanation:

We are given that the graph of the equation:

y=ax^2+bx+c

Passes through the three points (0, 5), (1, 10), and (2, 19).

And we want to find the value of (<em>a</em> + <em>b</em> + <em>c</em>).

First, since the graph passes through (0, 5), its <em>y-</em>intercept or <em>c</em> is 5. Hence:

y=ax^2+bx+5

Next, since the graph passes through (1, 10), when <em>x</em> = 1, <em>y</em> = 10. Substitute:

(10)=a(1)^2+b(1)+5

Simplify:

5=a+b

The point (2, 19) tells us that when <em>x</em> = 2, <em>y</em> = 19. Substitute:

(19)=a(2)^2+b(2)+5

Simplify:

14=4a+2b

This yields a system of equations:

\begin{cases} 5 = a + b \\ 14 = 4a + 2b\end{cases}

Solve the system. We can do so using elimination (or any other method you prefer). Multiply the first equation by negative two:

-10=-2a-2b

Add the two equations together:

(-10)+(14)=(-2a+4a)+(-2b+2b)

Combine like terms:

4 = 2a

Hence:

a=2

Using the first equation:

5=(2)+b\Rightarrow b=3

Therefore, our equation is:

y=2x^2+3x+5

Thus, the value of (<em>a</em> + <em>b</em> + <em>c</em>) will be:

a+b+c = (2) + (3) + (5) = 10

7 0
3 years ago
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