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salantis [7]
3 years ago
14

If the length of a rectangular yard is represented by w+4 and the width by 2w+5, write a simplified expression in terms of w tha

t represents the total length of fence needed to go around the yard. Show your work step by step.
Mathematics
1 answer:
adell [148]3 years ago
6 0

Answer:

P = 6w + 18

Step-by-step explanation:

A rectangle is a plane shape having a LENGTH and a WIDTH.

Length (l) = w + 4

Width (w) = 2w + 5

To write a simplified equation in terms of w to represent the total length, let's used the idea of a PERIMETER of a RECTANGLE.

Perimeter (P) = 2 ( l + b)

Where l = length= w + 4

Where b = width = 2w + 5

P = 2( w + 4 + 2w + 5)

P = 2( 3w + 9)

P = 6w + 18

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What is the quotient of 10?
olya-2409 [2.1K]

A quotient is the result of dividing one number by another. For example, the quotient of 6 and 3 equals 6/3 or 2. In your problem above it is asking you to provide the quotient of 10 and 2 meaning you divide the 2 into the ten and end up with 10/2 or 5.

So I think the answer is 10/2 or 5

5 0
2 years ago
NO ASSESSMENTS/NO LINKS!!
alexdok [17]

9514 1404 393

Answer:

  g(x) = x -1

Step-by-step explanation:

Translation of a function by (right, up) = (h, k) is accomplished by ...

  g(x) = f(x -h) +k

Here the translation is 4 units left, so h=-4 and k=0. This means ...

  g(x) = f(x +4) = (x+4) -5

  g(x) = x -1

3 0
3 years ago
Nigel wants to average 85% on his four tests. He got 77%, 89%, 78% on his first three tests. What does he need to get on his las
Arte-miy333 [17]

Answer:

He needs to get 96%

Step-by-step explanation:

Add 96 89 77 and 78 together and divide by 4, it should be 85

4 0
3 years ago
F(x) = 2x2 - 4x?; Find (-4)
anastassius [24]

Answer:

0 (zero)

Step-by-step explanation:

Plug in the variable for -4 and solve

y= 2(-4)2-4(-4)

y= -8(2)-4(-4)

y=-16+16

y=0

4 0
3 years ago
Solve.
Nikitich [7]
The answer is C: 10\text{ }^1/_2. Here are the details:

\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
16\text{ }^5/_6

\text{Equation:}\\
16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Start with the integers.}\\
16+3=19\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{...then with the fractions, but rewrite them first to make it easier.}\\
^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
20\text{ }^2/_3

\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add the integer and fraction together.}\\
25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6

26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6
5 0
3 years ago
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