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hram777 [196]
3 years ago
6

on Monday the number of customers in the store rounded to the nearest hundred was 400 what is the greatest number of customers t

hat could have been in the store
Mathematics
2 answers:
Zinaida [17]3 years ago
8 0
Well, if any number is higher than '5' it turns one number more. So, here's a good rhyme to help you: "Five or more, up the score, Four or less, let it rest." The maximum number it could be would have to be '444' because it is not bigger than 445, which would turn to 500.
tresset_1 [31]3 years ago
8 0

Answer:

The greatest number of customers that could have been in the store is 449.

Step-by-step explanation:

Consider the provided number information

Here, we need to round off to the nearest hundred.

The rule of rounding a number is:

If 0, 1, 2, 3, or 4 follow the number, then no need to change the rounding digit.

If 5, 6, 7, 8, or 9 follow the number, then rounding digit rounds up by one number.

Now, consider the number 400.

We want the greatest number that's rounds to 400.

For greatest number the number should be greater than 400. We don't want to increase the number at the Hundreds place, so the greatest possible choice for Tens place is 4. For the greatest number place 9 at ones place.

Hence, the greatest number is 449 because 449 rounded to nearest hundred is 400.

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Answer:

Cost of a coffee is <u>$2.5</u> and cost of a latte is <u>$4.25.</u>

Step-by-step explanation:

Let cost of 1 coffee be 'c' and cost of 1 latte be 'l' dollars.

Given:

4 coffees and 12 lattes cost $61.

12 coffees and 7 lattes cost $59.75.

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Now, as per question:

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Now, multiplying equation (1) by -3 and adding the result to equation (2). This gives,

-3(4c+12l)=-3(61)\\\\-12c-36l=-183\\12c+7l=59.75\\+\\----------\\0-29l=-123.25\\\\l=\frac{-123.25}{-29}=\$4.25

Now, plug in the value of 'l' in equation 1 to solve for 'c'. This gives,

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