1 centimeter = 10 millimeters
<span>
The correct statement of the problem is attached</span><span>Spinner A: 4 parts, 3/4 is 1, 1/4 is 3.----------1 1 1 3
Spinner B: 3 parts, 1/3 is 5, 1/3 is 7, 1/3 is 9--------5 7 9
</span><span>The combinations of the two spinners are
1 and 5
1 and 7
1 and 9
3 and 5
3 and 7
3 and 9
</span>
cases get you thrown in the pool
1 and 5
1 and 7
3 and 5
calculation of the probabilities
1 and 5--------3/4*1/3 = 1/4
1 and 7--------3/4*1/3 = 1/4
3 and 5--------1/4*1/3 = 1/12
1/4+1/4+1/12=7/12-----------
58.33%probabilities that the guests will be thrown in the pool--------58.33%
Sorry I’m wrong I took geometry like 3 years ago so I might forget some
11. SSS
12. AAS
13 Not possible
14. ASA
15. SAS
16.ASA
The length and width of the garden will be obtain as follows:
let the length be x ft, the width will be (x+3.5)ft
area of the bed will be:
A=length*width
11.76=x(x+3.5)
11.76=x^2+3.5x
thus
x^2+3.5x-11.76=0
solving this by quadratic formula we get:
x=[-b+/-sqrt(b^2-4ac)]/2a
thus plugging in the values we obtain
x=[-3.5+/-sqrt(3.5^2-4(-11.76*1))]/2
x=[-3.5+/-sqrt59.29]/2
x=[-3.5+/-7.7]/2
x=4.2 or -11.2
thus the length will be x=4.2 ft and the width will be x-3.5=0.7 ft
Look for a common number in all the terms
6(2a+3b-c)