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konstantin123 [22]
3 years ago
9

Lydia is trying to prove that a quadrilateral in a coordinate plane is a square. First, she uses the slope formula to prove that

there are two pairs of parallel sides. Next, she uses the distance formula to prove that all sides are equal. What additional step must Lydia perform before reaching a conclusion that the quadrilateral is a square?
Mathematics
2 answers:
ch4aika [34]3 years ago
7 0
To be classified as a square, a quadrilateral must have 2 pairs of parallel sides, 4 sides equal in length, and 4 right angles. By using the slope formula, it can be determined whether the quadrilateral's sides are perpendicular<span>. If so, 4 right angles exist and the shape is a square. If not, the shape is not a square.</span>
serg [7]3 years ago
6 0

Answer: Use the slope formula to prove that four right angles exist as a result of perpendicular sides.

Step-by-step explanation:

To be classified as a square, a quadrilateral must have 2 pairs of parallel sides, 4 sides equal in length, and 4 right angles. By using the slope formula, it can be determined whether the quadrilateral's sides are perpendicular. If so, 4 right angles exist and the shape is a square. If not, the shape is not a square.

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Fraction 3 over 4x = Fraction 1 over 5. x = ___?
umka21 [38]

Answer:

\large\boxed{x=3\dfrac{3}{4}}

Step-by-step explanation:

\dfrac{3}{4x}=\dfrac{1}{5}\qquad\text{cross multiply}\\\\(4x)(1)=(3)(5)\\\\4x=15\qquad\text{divide both sides by 4}\\\\x=\dfrac{15}{4}\\\\x=3\dfrac{3}{4}

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3 years ago
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5 0
3 years ago
5, 3.1.24<br><br> f(x) = 3x² + 5; find f(x + 3) - [f(x) + 3]
Aleks [24]

Given that f(x) = 3x^2 + 5, we have

f(x + 3) = 3 (x + 3)^2 + 5 \\\\= 3 (x^2 + 6x + 9) + 5 \\\\= 3x^2 + 18x + 32

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f(x+3) - (f(x) + 3) = (3x^2 + 18x + 32) - (3x^2 + 8) \\\\= \boxed{18x + 24}

3 0
2 years ago
If you distribute a negative factor, should you flip the inequality symbol? And why be specific
Alchen [17]
You flip is when you mulitply the whole equation by a negative
not when you distribute a  negative
if yo had
-3(x+4)>x
you wouldn't flip the negative symbol when distributing then -3

but if you had
-3(x+4)>-x
you would eventually have to multiply by -1 to make +1x

 
because they will be differente
exaple

12>3 is true
if yo multiply negative
-12>-3 is fale
-12<-3 is true

anothe rexample with placeholders
x<x+2
mulitply -1
-x>-x-2
false
-x<-x-2
true
that is why we flop the inequality symbole
6 0
4 years ago
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