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3241004551 [841]
2 years ago
10

I literally don't know how to figure this out i haven't done this in ages. Help please

Mathematics
1 answer:
Hitman42 [59]2 years ago
8 0
We begin with an unknown initial investment value, which we will call P. This value is what we are solving for.

The amount in the account on January 1st, 2015 before Carol withdraws $1000 is found by the compound interest formula A = P(1+r/n)^(nt) ; where A is the amount in the account after interest, r is the interest rate, t is time (in years), and n is the number of compounding periods per year.

In this problem, the interest compounds annually, so we can simplify the formula to A = P(1+r)^t. We can plug in our values for r and t. r is equal to .025, because that is equal to 2.5%. t is equal to one, so we can just write A = P(1.025).

We then must withdraw 1000 from this amount, and allow it to gain interest for one more year.

The principle in the account at the beginning of 2015 after the withdrawal is equal to 1.025P - 1000. We can plug this into the compound interest formula again, as well as the amount in the account at the beginning of 2016.

23,517.6 = (1.025P - 1000)(1 + .025)^1
23,517.6 = (1.025P - 1000)(1.025)

Divide both sides by 1.025

22,944 = (1.025P - 1000)

Add 1000 to both sides

23,944 = 1.025P

Divide both by 1.025 for the answer

$22,384.39 = P. We now have the value of the initial investment.

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Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

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Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

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Where \mu=5.75241 and \sigma=0.06281

And the best way to solve this problem is using the normal standard distribution and the z score given by:

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For the case when z =-2 we can do this:

-2 = \frac{X-5.75241}{0.06281}

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And for the other case when Z=2 we have:

2 = \frac{X-5.75241}{0.06281}

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X = 5.75241 +2*0.06281 =5.8886

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