Question

What is the first four terms of 3n²

Answer 1

Suppose there is a function $f(n)=3n^2, n\in\mathbb{N}$.

We start counting by 1 from the first element in domain of natural numbers so: 1, 2, 3, 4.

We assemble the definition set $A=\{1,2,3,4\}$ than use the function f(n) to create transformation set:

$f(A)=3\{1,2,3,4\}^2\Longrightarrow\{3,6,9,12\}^2 \\\boxed{B=\{9,36,81,144\}}$

So the first four terms are defined in transformation set B.

Hope this helps.

r3t40