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3 years ago

1

Mathematics

1 answer:

Annette [7]3 years ago

7 0

Answer:

Step-by-step explanation: If you do the math you can clearly see and I got the answer correct.

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Can someone please explain how to do this ?

prisoha [69]

$20=20f\\\\ f=1$

1 scoop

6 0

3 years ago

P+29=³√x make x the subject

Ksivusya [100]

Answer:

Step-by-step explanation:

P+29=³√x

Find the cube of both side

(P+29)³=(³√x)³

(P+29)³=x

7 0

3 years ago

Slope intercept form of a line that has a slope of -3/4 and passes through (4, 3)

tia_tia [17]

<h3>Explanation</h3>

First Method

We have the given slope value and the coordinate point that the graph passes through.

$y = mx + b$

where m = slope and b = y-intercept. Substitute the value of slope in the equation.

$y = - \frac{3}{4} x + b$

We have the given coordinate point as well. After we substitute the slope, we substitute the coordinate point value in the equation.

$3 = - \frac{3}{4} (4) + b \\$

Solve the equation for b-term

$3 = - 3 + b \\ 3 + 3 = b \\ 6 = b$

The value of b is 6. We substitute the value of b in the equation.

$y = - \frac{3}{4} x + 6$

Second Method

We can also use the Point-Slope form to solve the question.

$y - y_1 = m(x - x_1)$

Given the y1 and x1 = the coordinate point value.

Substitute the slope and coordinate point value in the point slope form.

$y - 3 = - \frac{3}{4} (x - 4)$

Simplify/Convert into Slope-intercept

$y = - \frac{3}{4} (x - 4) + 3 \\ y = - \frac{3}{4} x + \frac{12}{4} + 3 \\ y = - \frac{3}{4} x + 3 + 3 \\y = - \frac{3}{4} x + 6$

<h3>Answer</h3>

 $\large \boxed {y = - \frac{3}{4} x + 6}$ 

6 0

2 years ago

Is there enough information?

Minchanka [31]

Yea and the theorem is SAS

3 0

3 years ago

(1.)Find the slope of the line that passes through the given pair of points. (If an answer is undefined, enter UNDEFINED.) (?a +

jekas [21]

Answer:

1. The slope of the line is $m=\frac{-2b+3}{2a}$ .

2. The value of a is 18.

Step-by-step explanation:

If a line passes through two points, then the slope of the line is

$m=\frac{y_2-y_1}{x_2-x_1}$

(1)

It is given that the line passes through the points (-a + 3, b - 3) and (a + 3, -b). So, the slope of the line is

$m=\frac{-b-(b-3)}{a+3-(-a+3)}$

$m=\frac{-b-b+3}{a+3+a-3)}$

$m=\frac{-2b+3}{2a}$

The slope of the line is $m=\frac{-2b+3}{2a}$ .

(2)

If the line passing through the points (a, 1) and (6, 5), then the slope of the line is

$m_1=\frac{5-1}{6-a}=\frac{4}{6-a}$

If the line passing through the points (2, 7) and (a + 2, 1), then the slope of the line is

$m_2=\frac{1-7}{a+2-2}=\frac{-6}{a}$

The slopes of two parallel lines are same.

$m_1=m_2$

$\frac{4}{6-a}=\frac{-6}{a}$

On cross multiplication we get

$4a=-6(6-a)$

$4a=-36+6a$

$4a-6a=-36$

$-2a=-36$

Divide both sides by -2.

$a=18$

Therefore the value of a is 18.

8 0

3 years ago