What is one ecample of an odd trigonometric function? ecplain?
1 answer:
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Answer:
Step-by-step explanation:
Given equation is,
y = 3x² - 6x + 11
a). y = 3x² - 6x + 11
= 3(x² - 2x) + 11
= 3(x² -2x + 1 - 1) + 11
= 3(x² - 2x + 1) - 3 + 11
= 3(x - 1)² + 8
Comparing this equation with y = a(x - b)² + c
a = 3, b = 1 and c = 8
b). For minimum value of x,
Since, vertex of the graph is given by (b, c),
Minimum value of x will be,
x = b
x = 1
c). Vertex of the parabola → (b, c)
→ (1, 8)
For y-intercept,
By substituting x = 0 in the equation,
y = 3(0 - 1)² + 8
y = 11
Now we can sketch the graph by using the table of input - output values.
x -2 -1 0 1 2 3
y 35 20 11 8 11 20
A ratio of 3:2.
The easiest way to go about this is to divide the actual number of wins (18) by its corresponding element in the ratio.
So:
This means every element on the ratio has a value of 6.
The amount of element in the ratio that correspond to losses is 2.
Multiply the actual amount of matches per element in the ratio by the number of elements that represents the losses in the ratio.
Your answer:
<em>"The team lost 12 games."</em>