Answer:
C) 11
Step-by-step explanation:
65/5=13
91/7=13
182/14=13, therefore
143/13=11
So you need to come up with a perfect square that works for the x coefficients.
like.. (2x + 2)^2
(2x+2)(2x+2) = 4x^2 + 8x + 4
Compare this to the equation given. Our perfect square has +4 instead of +23. The difference is: 23 - 4 = 19
I'm going to assume the given equation equals zero..
So, If we add subtract 19 from both sides of the equation we get the perfect square.
4x^2 + 8x + 23 - 19 = 0 - 19
4x^2 + 8x + 4 = - 19
complete the square and move 19 over..
(2x+2)^2 + 19 = 0
factor the 2 out becomes 2^2 = 4
ANSWER: 4(x+1)^2 + 19 = 0
for a short cut, the standard equation
ax^2 + bx + c = 0 becomes a(x - h)^2 + k = 0
Where "a, b, c" are the same and ..
h = -b/(2a)
k = c - b^2/(4a)
Vertex = (h, k)
this will be a minimum point when "a" is positive upward facing parabola and a maximum point when "a" is negative downward facing parabola.
Answer:
y = 11.5
Step-by-step explanation:
Given 2 secants from an external point to the circle.
Then the product of the external part and the whole of one secant is equal to the product of the external part and the whole of the other secant, that is
6(6 + y) = 5(5 + 16)
36 + 6y = 5 × 21 = 105 ( subtract 36 from both sides )
6y = 69 ( divide both parts by 6 )
y = 11.5
Answer:
17
Step-by-step explanation:
-(-17)= 17
Answer:
The speed of the cars is 
Step-by-step explanation:
First we must first have the clear concept that 
or 
Our question is the speed of the cars then the variable to clear will be s.
Let's raise the equation for each car taking into account that we have the following data:
Car 1: 
, 
and 
Car 1: 
, 
and
The two cars travel the same distance so we will raise the distance formula for each car and then match them.
<em>Car 1</em>
<em>Car 2</em>
The speed of the cars is 32 km/hr
