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hram777 [196]
3 years ago
9

PLEASE HELP I really need help please heplp

Mathematics
1 answer:
Darya [45]3 years ago
6 0

Answer:

im not sure but i think its A

Step-by-step explanation:

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Determine the distance between point (x1, y1) and point (x2, y2), and assign the result to point distance. the calculation is: d
Ronch [10]

we are given two points as

(1.0, 2.0) and (1.0, 5.0)

so,

(x1, y1)= (1.0 , 2.0)

(x2, y2)= (1.0 , 5.0)

x1=1 , y1=2

x2=1 , y2=5

now, we can use distance formula

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

now, we can plug values

and we get

d=\sqrt{(1-1)^2+(5-2)^2}

d=\sqrt{(0)^2+(3)^2}

d=\sqrt{(3)^2}

d=3

so, distance between points is 3...........Answer

5 0
3 years ago
A DISASTER RELIEF GROUP DELIVERS 395 FIRST AID KITS. THE GROUP DELIVERS AN EQUAL NUMBER OF FIRST AID KITS TO 3 COUNTRIES. HOW MA
postnew [5]
395/3
about 132
Hope this helped
7 0
3 years ago
Read 2 more answers
The Department of Commerce in a particular state has determined that the number of small businesses that declare bankruptcy per
skad [1K]

Answer:

B) 0.1487

Step-by-step explanation:

Let X be the discrete random variable that represents the number of events observed over a given time period.  If X follows a Poisson distribution, then the probability of observing k events over the time period is:

P(X=k)=\frac{\lambda^{k} *e^{-\lambda} }{k!}

Where:

\lambda=Mean\\k=number\hspace{3}of\hspace{3}events\\e=Euler's\hspace{3}number

So, the probability that exactly 5 bankruptcies occur next month is:

P(X=5)=\frac{6.4^{5} *e^{-6.4} }{5!} =\frac{17.84083537}{120} =0.1486736281\approx0.1487

4 0
3 years ago
48.0g piece of metal is dropped into 50.0mL of water in a graduated cylinder. The water level rises to 62.4mL. What is the densi
luda_lava [24]
Subtract 50 mL from 62.4 mL to get the volume of the metal. Then, divide the mass (48g) by the volume to get your density
6 0
3 years ago
Read 2 more answers
The midpoint of AB is M (0, -3). If the coordinates of AA are (2, 1) what are the coordinates of BB?
frez [133]

Answer:

B(-2, -7)

Step-by-step explanation:

Midpoint is (0, -3)

A(x₁, y₁) B(x₂, y₂)

A(2, 1)

Midpoint = (\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2} )\\\\Midpoint = (\frac{2+ x_{2} }{2}, \frac{1 + y_{2} }{2} )

(0, -3) = (\frac{2+ x_{2} }{2}, \frac{1 + y_{2} }{2} )

              \frac{2+ x_{2} }{2} = 0\\\\2 + x_{2} = 0\ \ \ \ times\ both\ sides\ by\ 2\\x_{2} = -2\ \ \ \ subtract\ both\ sides\ by\ 2

              \frac{1 + y_{2} }{2} = -3\\\\1 + y_{2} = -6\ \ \ \ times\ both\ sides\ by\ 2\\y_{2} = -7\ \ \ \ subtract\ both\ sides\ by\ 1

∴ B(-2, -7)

6 0
2 years ago
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