Answer: 20 km
Step-by-step explanation: Let's assume a trajectory of Ships A (which is moving at 6 km/h) and B (which is moving at 4 km/h)
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A 10 km B
And let's assume that who is going to the right is the positive.
Space (S) = S₀ + vt
For A, its space is SA = 0 + 6t
For B, its space is SB = 10 - 4t
They meet at SA = SB;
6t = 10 - 4t
6t + 4t = 10
10t = 10
t = 1h
If the bird is at 20 km/h and it will fly for 1h, it will travel 20 km
Their average is <em>59/144 .</em>
Her height would be h<5 feet
Answer:
Yes, 12:18 is simplified to 2:3
Step-by-step explanation:
Answer:
Size of groups known: First and last questions (The rice and cups ones)
Number of groups known: Second and third questions (Cars and hats)
Step-by-step explanation:
In the first problem, you know that one sack is one group, and it tells you that each sack weighs 3 kg. Therefore, you know the size of the group (or a sack).
In the last one, you know that a table is one group and each table fits 4 cups. So, you know that the size of the group is 4 cups.
In the second and third questions, you know that each group is a row (cars) or "equal group" (hat) and that there are 4 of each. So, you know that there are 4 of each group, meaning you know the "number of groups"
