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Vladimir79 [104]
2 years ago
14

(x – 4)(x + 10) = -17

Mathematics
1 answer:
pogonyaev2 years ago
4 0

Answer:

-3 +   4sqrt(2)

-3  -  4sqrt(2)

Step-by-step explanation:

(x – 4)(x + 10) = -17

FOIL on the left hand side  (First outer inner last)

x^2 +10x-4x-40 = -17

x^2 +6x-40 =-17

Add 17 to each side

x^2 +6x-40+17 =-17+17

x^2 +6x -23 = 0

Using the quadratic formula

-b + - sqrt(b^2 -4ac)

-------------------------------

   2a        

where ax^2 +bx+c=0

-6 + - sqrt(6^2 -4*1*-23)

-------------------------------

   2*1

-6 + - sqrt(36 +92)

-------------------------------

   2

-6 + - sqrt(128)

-------------------------------

   2

-6 + -  8sqrt(2)

-------------------------------

   2

Divide top and bottom by 2

-3 + -  4sqrt(2)

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If PQ = 3, QR = 2x, and PR = 3x, what is QR?
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Answer:

6

Step-by-step explanation:

It is ALWAYS helpful to sketch the appropriate figure.

That will make clear that 3x = x+4, by the definition of midpoint.

Then you solve the equation and you get x=2, so that PQ = 6.

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A curved graph could be a example of
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Step-by-step explanation:

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3 years ago
If f(x)= 6x+7, determine the value of f(-5)
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5 0
3 years ago
Read 2 more answers
The polynomial of degree 3 , P ( x ) , has a root of multiplicity 2 at x = 2 and a root of multiplicity 1 at x = − 3 . The y -in
lesya [120]

Answer:

P ( x ) = -0.7 (x - 2)²(x + 3)

Step-by-step explanation:

<u>We are given</u> :

P ( x ) , has a root of multiplicity 2 at x = 2

and a root of multiplicity 1 at x = − 3

Then

P ( x ) = a (x - 2)²(x + 3)  ; where ‘a’ is a real number.

P ( x ) = a (x - 2)²(x + 3)

= a (x² - 4x + 4)(x + 3)

= a [x³ - 4x² + 4x + 3x² - 12x + 12]

P (0) = -8.4

⇔ a [(0)³ - 4(0)² + 4(0) + 3(0)² - 12(0) + 12] = -8.4

⇔ 12 a  = -8.4

⇔  a  = (-8,4) ÷ 12

⇔  a  = -0,7

<u>Conclusion</u> :

P ( x ) = -0.7 (x - 2)²(x + 3)

4 0
1 year ago
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