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Vladimir79 [104]
3 years ago
14

(x – 4)(x + 10) = -17

Mathematics
1 answer:
pogonyaev3 years ago
4 0

Answer:

-3 +   4sqrt(2)

-3  -  4sqrt(2)

Step-by-step explanation:

(x – 4)(x + 10) = -17

FOIL on the left hand side  (First outer inner last)

x^2 +10x-4x-40 = -17

x^2 +6x-40 =-17

Add 17 to each side

x^2 +6x-40+17 =-17+17

x^2 +6x -23 = 0

Using the quadratic formula

-b + - sqrt(b^2 -4ac)

-------------------------------

   2a        

where ax^2 +bx+c=0

-6 + - sqrt(6^2 -4*1*-23)

-------------------------------

   2*1

-6 + - sqrt(36 +92)

-------------------------------

   2

-6 + - sqrt(128)

-------------------------------

   2

-6 + -  8sqrt(2)

-------------------------------

   2

Divide top and bottom by 2

-3 + -  4sqrt(2)

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Solve the equations if possible <br><br> * -5×=×+6(1-×)<br><br> *(2×-5)²=(2×-1)(2×+1)-10(2×-1)
Allushta [10]
-5x = x + 6(1-x)

-5x = x + 6(1) + 6(-x)
-5x = x + 6 -6x
-5x = x - 6x + 6
-5x = -5x + 6
-5x + 5x = 6
0 = 6  Not equal. No solution.

(2x-5)² = (2x-1)(2x+1) -10(2x-1)
(2x-5)(2x-5) = (2x-1)(2x+1) - 20x + 10
2x(2x-5)-5(2x-5) = 2x(2x+1)-1(2x+1) - 20x + 10
4x² - 10x -10x + 25 = 4x² + 2x - 2x -1 - 20x + 10
4x² - 20x + 25 = 4x² - 20x - 1 + 10
4x² - 20x + 25 = 4x² - 20x - 9

Not equal. No solution.

8 0
3 years ago
Find the volume of a pyramid with a square base, where the side length of the base is
Alexxandr [17]

Answer:

127.253 m^3

Step-by-step explanation:

To find the volume, we start by getting the area of the square base

Mathematically, that will be 4.9^2 m^2

To complete the volume, we multiply the area of the base by the height

= 4.9^2 * 5.3 = 127.253 m^3

4 0
3 years ago
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Mr. Sands drove 15 miles to the airport. When he was 3/5 of the way, he stopped for gasoline. How far did Mr. Sands drive before
irinina [24]

Answer:

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Step-by-step explanation:

15/5=3

so 3x3= 9 miles

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3 years ago
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Gnesinka [82]

Answer:

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Step-by-step explanation:

A^2+31^2=36^2

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3 years ago
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35 Points!!
nexus9112 [7]

Answer:

- Equal midpoints of AC and BC.

- The product of the slopes of the diagonals AC and DB is -1.

Step-by-step explanation:

1. Plot the given points, as you can see in the graph attached.

2. Calculate the midpoint of AC and DB:

M_{AC}=(\frac{-5+(-1)}{2},\frac{-1+5}{2})=(-3,2)\\M_{DB}=(\frac{-9+3}{2},\frac{6+(-2)}{2})=(-3,2)

Therefore, the midpoint of AC and DB are equal.

3. Calculte the slope of the diagonals AC and DB:

m_{AC}=\frac{5-(-1)}{-1-(-5)}=\frac{3}{2}\\m_{DB}=\frac{-2-6)}{3-(-9)}=-\frac{2}{3}

4. Multiply the slopes of the diagonals:

(\frac{3}{2})(-\frac{2}{3})=-1 (AC and DB are perpendicular)

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