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jek_recluse [69]
3 years ago
15

What’s the slope of this ??

Mathematics
1 answer:
aliya0001 [1]3 years ago
7 0

Answer:

If I'm not mistaken the slope is 7

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-5 1/2 + 6 3/4 + (-4 1/4) =
Sergeeva-Olga [200]

Answer:

-3

Step-by-step explanation:

8 0
2 years ago
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(8x10^-3) ÷ (2x10^-4)​
Lorico [155]

Answer:

40

Step-by-step explanation:

8*10^-3=0.003

2*10^-4=0.0002

0.003÷0.0002=40

5 0
3 years ago
What is the mass, in grams, of the object being measured in the triple beam balance shown below?
muminat

Answer:

  102.5 g

Step-by-step explanation:

The mass is the sum of the values indicated by the sliders:

  100 g + 0 g + 2.5 g = 102.5 g

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3 years ago
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arrange the circles (represented by their equations in general form) in ascending order of their radius lengths,  x^+y^-2x+2y-1=
Lubov Fominskaja [6]
From the order you gave me in the question the answer is equation number 
4 1 3 2 6 5
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7 0
3 years ago
A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas
WITCHER [35]

Answer:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

P(A) = 0.8, P(B) = 0.2

We are assuming that the two events are independent so then we have the following propert:

P(A \cap B ) = P(A) * P(B)

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

P(B' \cup A')

And using the De Morgan laws we know that:

(A \cap B)' = A' \cup B'

So then we can write the probability like this:

P(B' \cup A') = P((A \cap B)')

And using the complement rule we can do this:

P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)

Since A and B are independent we have:

P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32

And then our final answer would be:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

5 0
3 years ago
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