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3 years ago

What type of angle is shown ?

Mathematics

2 answers:

Schach [20]3 years ago

8 0

Obtuse. when its bigger than 90degrees

mariarad [96]3 years ago

4 0

Its an obtuse angle, just btw

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3 years ago

Find polynomial from zeros<br> Zeros 3i,2-i

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Y=x4−4x3+14x2−36x+45

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3 years ago

Sam paid $8.28 for 18 stamps.at this rate,how much would it cost Sam to buy 12 stamps

bixtya [17]

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3 years ago

Find sin θ and cos θ if tan θ= 1/4 and sin 0>0.

Serga [27]

Answer:

$\displaystyle \sin(\theta)= \frac{\sqrt{17}}{17}$

$\displaystyle \cos(\theta)= \frac{4 \sqrt {17} }{ 17 }$

Step-by-step explanation:

We want to find sin(θ) and cos(θ) given that tan(θ) = 1/4 and sin(θ) > 0.

First, since tan(θ) and sin(θ) are both positive, cos(θ) must be positive as well.

Recall that tangent is the ratio of the opposite side to the adjacent side.

Therefore, the hypotenuse is:

$h=\sqrt{4^2+1^2}=\sqrt{16+1}=\sqrt{17}$

So, with respect to θ, the opposite side is 1, the adjacent is 4, and the hypotenuse is √17.

Then it follows that:

$\displaystyle \sin(\theta)=\frac{1}{\sqrt{17}} = \frac{\sqrt{17}}{17}$

And that:

$\displaystyle \cos(\theta)= \frac{4}{\sqrt{17}} = \frac{4 \sqrt {17} }{ 17 }$

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3 years ago

What is the polar form of Negative 9 StartRoot 3 EndRoot + 9 i?

kondor19780726 [428]

Answer:

Step-by-step explanation:

In the rectangular complex number -9√3 + 9i, which has a standard form a + bi, the a = -9√3 and the b = 9. We need this in polar form (r, θ) where

$r=\sqrt{a^2+b^2}$ and filling in:

$r=\sqrt{(-9\sqrt{3})^2+(9)^2 }$ (notice we do not put the i in there with the 9).

$r=\sqrt{243+81}$ so

r = 18. Now let's move on to the angle, which is a little more difficult. The angle is found in the inverse tangent ratio:

$tan^{-1}(\frac{b}{a})$ so filling that in, we have:

$tan^{-1}(\frac{9}{-9\sqrt{3} })=\frac{1}{-\sqrt{3} }$ Since tangent is the side opposite over the side adjacent, y is positive and x is negative in the second quadrant. This is a 30 degree angle in QII, which has a reference angle of 150 degrees. This angle in radians is $\frac{5\pi}6}$ , so the polar form of that number is (18, $\frac{5\pi}{6}$ )

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3 years ago