All categories

3 years ago

Which is the equation for the nth term of the geometric sequence-2, 8, -32, ... ?

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

The square below represents one whole. What percent is represented by the shaded area?

Lelu [443]

the correct answer is 61%

6 0

2 years ago

What is the length of a rectangle whose perimeter is P, if the width is 6? please help asap!!

aliina [53]

(P-12)/2 ................................................................\

6 0

3 years ago

Please help I don’t understand this..

Paraphin [41]

Answer:

its your problems

Step-by-step explanation:

your job is to find solutions by your self

and thank me later

4 0

3 years ago

Find the volume of the solid generated by revolving the region bounded by

Rama09 [41]

Answer:

$V =\dfrac{25\pi}{\sqrt{2}}$

Step-by-step explanation:

given,

y=5√sinx

Volume of the solid by revolving

$V = \int_a^b(\pi y^2)dx$

a and b are the limits of the integrals

now,

$V = \int_a^b(\pi (5\sqrt{sinx})^2)dx$

$V =25\pi \int_{\pi/4}^{\pi/2}sinxdx$

$\int sin x = - cos x$

$V =25\pi [-cos x]_{\pi/4}^{\pi/2}$

$V =25\pi [-cos (\pi/2)+cos(\pi/4)]$

$V =25\pi [0+\dfrac{1}{\sqrt{2}}]$

$V =\dfrac{25\pi}{\sqrt{2}}$

volume of the solid generated is equal to $V =\dfrac{25\pi}{\sqrt{2}}$

4 0

3 years ago

Two cargo ships are sailing a direct course into harbor. Ship A is 22 miles from harbor. Ship Bis sailing into harbor on a cours

s344n2d4d5 [400]

Answer:

The distance of ship B from the Harbor is 32.26 miles

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.

I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the COSINE operator to solve for the length of the course of ship B.

$cos(x) = \frac{adjacent}{hypotenuse}$