How do you solve |8y 4|=2|y-1|

what is a rational number that is between 5.2 and 5.5. what is a irrational number that is between 5.2 and 5.5.

Katyanochek1 [597]

5.2 < x < 5.5
square
5.2² < x² < 5.5²
27.04 < x² < 30.25
Pick any number for between 27.04 and 30.25 for x², as long as it's not a perfect square. So you could pick 30.

x² = 30

x = √30 → irrational number between 5.2 and 5.5

8 0

4 years ago

Let set A = {1,3,5,7} and set B = {1,2,3,4,5,6,7,8}

Semenov [28]

Step-by-step explanation:

A elements lies on B.............

4 0

4 years ago

Please help! Math problem attached below.

Arturiano [62]

<h3>Answer: D) $16.77</h3>

=====================================================

Explanation:

The meter goes from 9854 to 0023. You can think of 0023 as 10023 (even though the meter only has 4 digits, so it rolls over to start over again).

So,

10023 - 9854 = 169

This means 169 kw hours of electricity are used for the month of December.

The first 100 kw hours costs $4.35

There are 169-100 = 69 kw hours left, and they cost $0.18 each, so we add on 69*0.18 = 12.42 getting 4.35 + 12.42 = 16.77

4 0

4 years ago

What is the answer to 4 - 8n + 7n - 3n - 9

MArishka [77]

The answer is -5-4n
You get rid of the 4 and the -9
And then you combine all the terms with the n

7 0

4 years ago

Read 2 more answers

Consider the probability that no less than 95 out of 152 registered voters will vote in the presidential election. Assume the pr

nikdorinn [45]

Answer:

0.3821 = 38.21% probability that no less than 95 out of 152 registered voters will vote in the presidential election.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

Assume the probability that a given registered voter will vote in the presidential election is 61%.

This means that $p = 0.61$

152 registed voters:

This means that $n = 152$

Mean and Standard deviation:

$\mu = E(X) = 152*0.61 = 92.72$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{152*0.61*0.39} = 6.01$

Probability that no less than 95 out of 152 registered voters will vote in the presidential election.

This is, using continuity correction, $P(X \geq 95 - 0.5) = P(X \geq 94.5)$ , which is 1 subtracted by the pvalue of Z when X = 94.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{94.5 - 92.72}{6.01}$

$Z = 0.3$

$Z = 0.3$ has a pvalue of 0.6179

1 - 0.6179 = 0.3821

0.3821 = 38.21% probability that no less than 95 out of 152 registered voters will vote in the presidential election.

6 0

3 years ago