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rosijanka [135]
2 years ago
14

Determine the midpoint of the segment with endpoints (–10, –11) and (8, –17).

Mathematics
1 answer:
nataly862011 [7]2 years ago
6 0

Answer:

Midpoint: (-1, -14)

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Which of the following inequalities are true? Select all of the correct
Scorpion4ik [409]

477>80 is correct

-4.5<3 this one is also correct

8 0
3 years ago
If you are reading this please help!!!!
Soloha48 [4]

Given:

1.  -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$

To find:

The product of the polynomials.

Solution:

1. -3 x^{2}\left(4 x^{3}-7\right) =-3 x^{2}(4 x^{3}) -3 x^{2}(-7)

Multiply the numerical coefficient and add the powers of x.

                          =-12 x^{5}+21 x^{2}

2. (6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                              =12 x^2+18x-10 x-15

                              =12 x^2+8x-15

3. (3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                                      =3x^{3}+15 x^2-6x-x^{2}-5 x+2

Add or subtract like terms together.

                                      =3x^{3}+14 x^2-11x+2

The answer for multiplying polynomials:

1. -12 x^{5}+21 x^{2}

2. \  12 x^2+8x-15

3. \ 3x^{3}+14 x^2-11x+2

3 0
3 years ago
Solve the following equation for n 18n^2-50=0
Firdavs [7]

18n^2-50=0\ \ \ |+50\\\\18n^2=50\ \ \ |:18\\\\n^2=\dfrac{50}{18}\\\\n^2=\dfrac{50:2}{18:2}\\\\n^2=\dfrac{25}{9}\to n=\pm\sqrt{\dfrac{25}{9}}\\\\n=\pm\dfrac{\sqrt{25}}{\sqrt{9}}\\\\\boxed{n=-\dfrac{5}{3}\ \vee\ n=\dfrac{5}{3}}

Used:\\\sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}

3 0
3 years ago
I need help please!!!
marusya05 [52]
A) 1.5, you can cross off C and D because that's area. the only reasonable would be 1.5 and 5.8. But 5.8 would mean cutting half of the board. 
3 0
2 years ago
You are working with cable that has a loss rate of 5 dB per 100 ft. If you don’t want to lose more than 15 dB, what is the maxim
pochemuha
300 ft

5 • 3 = 15
100 • 3 = 300
6 0
3 years ago
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