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vampirchik [111]
3 years ago
15

What is the √84 in radian form?

Mathematics
1 answer:
irga5000 [103]3 years ago
4 0
The answer to this question is 9
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IgorLugansk [536]

Answer:

hi

Step-by-step explanation:

8 0
3 years ago
Can I get some help with this? Thanks​
iris [78.8K]

Step-by-step explanation:

first you need to know that angle 4 and angle d are the same measurement. so then you have to notice that a straight line is equal to 180 degrees. by knowing this you can make this equation

x+30+ 2x +15= 180

next combine like terms:

3x+ 45=180

next subtract 45 from both sides

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next divide by 3 on both sides to get x alone. this will give you your answer.

x=45

once you know this plug 45 into you equation to do d the value of the angle 4

5 0
3 years ago
Find K by evaluating Limit
Lubov Fominskaja [6]

Answer:

4

Step-by-step explanation:

\lim_{x \to \infty}\frac{1-cos4x}{1-cos2x}= \lim_{x \to 0} \frac{(1-cos4x)'}{(1-cos2x)'}= \lim_{x \to 0}\frac{4sin4x}{2sin2x}= \lim_{x \to 0}\frac{2*2sin2xcos2x}{sin2x}\\ = \lim_{x \to 0}4cos2x\\ =4

{L'Hospital's rule}

<em>I hope this helps you</em>

<em>:)</em>

6 0
2 years ago
lemon squash 2 parts concentrate to 5 parts of water. if you put 90ml of concentrate in a glass, how much water should be added?
snow_lady [41]

It is given in the question that in the lemon squash 2 parts concentrate is added to 5 parts of water. Thus it makes the concentrate to water ratio as 2:5 or \frac{2}{5}. Now, if this ratio is maintained then the amount of water to be added to 90 ml concentrate in a glass can be calculated as:

\frac{2}{5}=\frac{90}{x}

Where x is the amount of water to be added, in ml (milliliters).

Cross multiplication of the above equation will give us:

2x=90\times 5=450

Dividing both sides by 2 we will get:

x=\frac{450}{2}=225

Thus, if we put 90ml of concentrate in a glass, the water that should be added must be 225 ml.


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4 years ago
Write an expression to show show many fewer medals Australia won than Great Britain
tamaranim1 [39]
If this is math where is the number or is it just word problem
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