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3 years ago

How much interest is earned on a pricipal of $267 invested at an interest rate of %6 for six years?

Mathematics

1 answer:

Marianna [84]3 years ago

5 0

The correct answer is, 16.02.

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Is (1, 4) a solution to the equation y = 7x?

olga nikolaevna [1]

Answer:

not a solution

Step-by-step explanation:

Substitute the point into the equation and see if it is true

y = 7x

4 = 7*1

4 = 7

This is not true so it is not a solution

8 0

3 years ago

What is the number form of 26.96 million?

Alik [6]

For example: 26 million = 26,000,000 and 0.96 million = 960,000.
Answer:
26.96 million = 26,960,000
Thank you.

4 0

3 years ago

Help help math math math

damaskus [11]

Answer:

2x+y=6

Step-by-step explanation:

The standard form of such an equation is Ax + By + C = 0 or Ax + By = C. When you rearrange this equation to get y by itself on the left side, it takes the form y = mx +b. This is called slope-intercept form because m is equal to the slope of the line, and b is the value of y when x = 0, which makes it the y-intercept.

4 0

3 years ago

1. Find the derivative of f(x), at x = 10<br> f(x) = - 5x² + 13x

Serhud [2]

Answer:

-10x+13

Step-by-step explanation:

Im not 100% sure but i tried!

6 0

3 years ago

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

Leni [432]

Answer: $\dfrac{2x^2-1}{x(x^2-1)}$

Step-by-step explanation:

The given function : $y=\ln(x(x^2 - 1)^{\frac{1}{2}})$

$\Rightarrow\ y=\ln x+\ln (x^2-1)^{\frac{1}{2}}$ [ $\because \ln(ab)=\ln a +\ln b$ ]

$\Rightarrow y=\ln x+\dfrac{1}{2}\ln (x^2-1)}$ [ $\because \ln(a)^n=n\ln a$ ]

Now , Differentiate both sides with respect to x , we will get

$\dfrac{dy}{dx}=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})\dfrac{d}{dx}(x^2-1)$ (By Chain rule)

[Note : $\dfrac{d}{dx}(\ln x)=\dfrac{1}{x}$ ]

$\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x-0)$

[ $\because \dfrac{d}{dx}(x^n)=nx^{n-1}$ ]

$=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x) = \dfrac{1}{x}+\dfrac{x}{x^2-1}\\\\\\=\dfrac{(x^2-1)+(x^2)}{x(x^2-1)}\\\\\\=\dfrac{2x^2-1}{x(x^2-1)}$

Hence, the derivative of the given function is $\dfrac{2x^2-1}{x(x^2-1)}$ .

8 0

4 years ago