Let's say make the shapes, some variable name

say

⛁ ⚪ ◽ ▯
a b c d

so.. if take those are the shapes provided

then we can take a look at the first set and we can say that

2a + b + c = 20

a + 4d + b = 19

a + c = 9

3c + d + a = 19

thus $\bf \begin{cases}
2a + b + c = 20\\
a + 4d + b = 19\\
a + c = 9\\
3c + d + a = 19 
\end{cases}\\\\
-----------------------------\\\\
a+c=9\implies \boxed{c}=9-a\qquad thus
\\\\\\
2a+b+\boxed{9-a}=20\implies \underline{b}=11-a\impliedby thus
\\\\\\
a+4d+\underline{11-a}=19\implies d=\cfrac{8}{4}\implies d=2\\\\
-----------------------------\\\\
then\qquad 3\left(\boxed{9-a } \right)+\boxed{2}+a=19\implies 27-3a+2+a=19
\\\\\\
10=2a\implies 5=a$

and surely you can find the other two

4 0

3 years ago

Match the base to the corresponding height

Black_prince [1.1K]

The are both equal bc you use the graphing method or I was taught that

8 0

3 years ago