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Blizzard [7]
2 years ago
7

Mia has two ribbons. One is 60 cm long and the other is 45 cm long Mia cuts both ribbons into pieces. All the pieces have the sa

me length. Find the greatest possible length of each piece of ribbon​
Mathematics
1 answer:
Dafna11 [192]2 years ago
7 0

List factors of each:

60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

45: 1, 3, 5, 9, 15, 45

The largest common value is 15

The greatest possible length of each is 15 cm

Answer: 15 cm.

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Step-by-step explanation:

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3 years ago
This is fairly easy yet i cannot do this
ICE Princess25 [194]

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( -9, -6)

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3 years ago
Perform the indicated operation.(7 - 11/) + (-3 + 5/)
den301095 [7]

Answer:

<u>The correct answer is C. 4 -6</u>

Step-by-step explanation:

Let's solve the operation given, this way:

(7 - 11/) + (-3 + 5/)

7 - 11 - 3 + 5=

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4 0
3 years ago
Ty in advance for whoever does this. Find the range and put it on the graph. thank you &lt;3
ser-zykov [4K]

Answer:

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y_{1} = - 4 - 2( - 3) = 2

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y_{4} = - 4 - 2( 0 ) = - 4

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8 0
3 years ago
Please help!! I’ll mark brainliest
Aleks04 [339]

The triangle was only rotated. The size did not change, so the corresponding angles would remain identical.

Because C is 28 degrees C' would also be 28 degrees.

3 0
3 years ago
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