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igomit [66]
3 years ago
13

Right two division equation for each multiplication equation

Mathematics
1 answer:
Andru [333]3 years ago
6 0

Which describes the effect of the transformations on the graph of ƒ(x) = x2 when changed to ƒ(x) = 3(x + 2)2 − 4?

A) stretched vertically, shifted left 2 units, and shifted down 4 units  

B) stretched vertically, shifted right 2 units, and shifted up 4 units  

C) compressed vertically, shifted left 2 units, and shifted down 4 units  

Eliminate

D) compressed vertically, shifted right 2 units, and shifted up 4 units

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The diameters of ball bearings are distributed normally. The mean diameter is 83 millimeters and the standard deviation is 3 mil
Alenkinab [10]

Answer:

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 83, \sigma = 3

Find the probability that the diameter of a selected bearing is greater than 85 millimeters.

This is 1 subtracted by the pvalue of Z when X = 85. Then

Z = \frac{X - \mu}{\sigma}

Z = \frac{85 - 83}{3}

Z = 0.67

Z = 0.67 has a pvalue of 0.7486.

1 - 0.7486 = 0.2514

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

7 0
3 years ago
1. as.at<br>2. (a/b)2 (a/b)<br>8<br>3. (3)-5<br>4. (x/y)"<br>5. (2m4n3)5<br>​
Nikolay [14]
1- I didn't understand it

2).. (a/b)² (a/b)⁸

= (a/b)²+⁸ = (a/b)¹⁰

3) 3-⁵ = 1/3⁵ = 1/243

4) (x/y)"

d/dx (x/y) = (1/y)
d/dx (1/y) = 0

5) (2m⁴n³)⁵

= 2⁵ × (m⁴)⁵ × (n³)⁵

= 32 × m²⁰ × n¹⁵

= 32m²⁰n¹⁵
5 0
2 years ago
What’s the y-intercept? i found the slope already.
Valentin [98]

Answer:

3.5

Step-by-step explanation:

3.5 is the y-intercept because the point is (0,3.5). This is where it intercepts with the y-axis.

Hope it helps!

6 0
3 years ago
Prove that the curve a(t) = (cost, sin 2t, cos 2t) is regular on R and that it self-intersects at (1,0,1). Check the self-inters
alexandr402 [8]

Answer:

The function a (t) is a vector function composed of the component functions a_ {1} (t) = cost, a_ {2} (t) = sin2t and a_ {3} (t) = cos2t. How a_ {1} (t), a_ {2} (t), a_ {3} (t) are infinitely derivable functions in R, so they are regular functions in R.

Now, fort = 0, you have to a (0) = (cos (0), sin2 (0), cos2 (0)) = (1, 0, 1). How the functions a_ {1} (t), a_ {2} (t), a_ {3} (t) are periodic functions with period 2 \pi, the vector function a (t) will take the same point (1, 0 , 1) at t = 2n\pi, n = 0, 1, 2, 3, ... then the vector function is auto-intercepted

Step-by-step explanation:

6 0
3 years ago
Living with parents: A Pew Research analysis stated that in 2012, 36% of the nation’s young adults ages 18 to 31—the so-called M
Galina-37 [17]

Answer:

b.0.02

Step-by-step explanation:

As he defined the significance level in α=0.05, and this is a one-side test (as the claim is that the percentage is <em>higher, </em>not lower), any P-value below the significance level shows a significant effect and gives evidence to reject the null hypothesis.

The P-value represents the probability of having this sample statistic, given that the statement of the null hypothesis is true. Then, the lower the P-value, more evident is that the null hypothesis is not correct. This threshold value to reject (or not) the null hypothesis is the significance level.

a) As the significance level is 0.05, a P-value=0.07 would not be low enough to reject the null hypothesis.

c) The magnitude of a P-value has impact on whether he rejects or fails to reject the null hypothesis, as is the value that is compared to the significance level to reject or not the null hypothesis.

7 0
3 years ago
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