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antiseptic1488 [7]
4 years ago
6

What is the measure of the angle?​

Mathematics
1 answer:
NikAS [45]4 years ago
6 0

Answer: My guess would be 120° .

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Find the LCM and HCF of 110 and 220 by prime factorization what do you observe....pls answer this ​
ElenaW [278]

Answer: Check if numbers are prime. Composite numbers prime factorization (decomposing, breaking numbers down to prime factors). Inscribe them as a product of prime factors, in exponential notation.

8 0
3 years ago
-5+7=7+-5 is this number sentence true or false
vovikov84 [41]

Answer: True

Step-by-step explanation:

We can simplify each of the expressions on either side to see if they are equal.

Left side: -5+7=7-5= 2

Right side: 7+-5=7-5= 2

Yes, they are equal.

7 0
2 years ago
Read 2 more answers
PLS HELP ME!!!!!!!!!!
KonstantinChe [14]

Answer:

1)  yes, SAS

2)  yes, AAS

3)  yes, SAS

4)  not enough information to know

Step-by-step explanation:

6 0
3 years ago
12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests
Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that p = 0.12.

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so n = 18

This probability is:

P = P(X = 0) + P(X = 1)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{18,0}.(0.12)^{0}.(0.88)^{18} = 0.1002

P(X = 1) = C_{18,1}.(0.12)^{1}.(0.88)^{17} = 0.2458

So

P = P(X = 0) + P(X = 1) = 0.1002 + 0.2458 = 0.3460

There is a 34.60% probability that 0 or 1 of them is nearsighted.

5 0
4 years ago
What number is less than -2 4/5 and greater than -31/5
IgorC [24]

Using a calculator, you should find that

-2 & 4/5 = -(2 + 4/5) = -(2+0.8) = -2.8

-31/5 = -6.2

So the unknown number is between -6.2 and -2.8

<h3>Possible whole number answers could be: -6, -5, -4, -3, or -2</h3>

If your teacher allows decimal answers, then there are infinitely many possible ways to answer.

8 0
3 years ago
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