45 | 45 divided by 5 = 9
So i think if we do the same for 70 we will get the length
70| 70 divided by 5 = 14
So the length = 14
--If I'm incorrect please correct me
<h2>
Answer:</h2>
BC ≅ 11cm
<h2>
Step-by-step explanation:</h2>
To accomplish this task, follow these steps:
i. Using your ruler, draw a line AB with length 8cm as shown in Figure 1. This will give AB = 8cm
ii. Remove the ruler and place your protractor at the point A and parallel to line AB as shown in Figure 2. Make a dot at the mark 90° of the protractor (See Figure 2). For accuracy, ensure that the 180° mark of the protractor is on the line AB.
iii. From point A through the dot in (ii) above, use a ruler to draw a line AC of length 8cm as shown in Figure 3. This will give AC = 8cm and will also give angle CAB = 90°
iv. Now join points C and B by drawing a line from point A to C using a ruler as shown in Figure 4.
v. Lastly, measure the length of BC by placing your ruler on line BC as shown in Figure 5. This should give a value of about 11cm.
Therefore the length of BC = 11cm approximately.
<em>NB: All figures are attached to this response. </em>
Answer:
2190 r. 4
Step-by-step explanation:
4 REMAINING
Subtracting 1 from the function notation will decrease the y-values on the graph by 1 unit.
This will shift then entire graph of f down by 1 unit to create the graph of g.
The best way to solve this problem is with a simple equation: part = percent (in decimal form) x whole
In this problem, we're trying to solve for the <em>whole </em>amount that the camera can hold, so we'll assign that the variable w.
We can use the information they gave us - 96 is the <em>part</em>, and 24% is the percent. We'll convert that to decimal form - 0.24
Then, we just plug these values back into the above equation:
96 = 0.24w
Divide both sides by 0.24 to get w on it's own, and you have your answer!
400 = w
Therefore, the memory card can hold up to 400 pictures.
Note: this equation is <em>super </em>helpful. It's good to have on hand for any problem involving percents, because you can solve for the part, percent, or whole depending on the problem.
