Answer:
15.59 feet
Step-by-step explanation:
We need to find BC and CD
First find BC
We can use the Pythagorean theorem
AB^2 + BC^2 = AC^2
11^2 + BC^2 = 13^2
121 + BC^2 =169
Subtract 121 from each side
121-121+BC^2 = 169-121
BC^2 = 48
Take the square of each side
sqrt(BC^2 ) = sqrt( 48)
BC = 6.92820323
then we need to find CD
We can use the Pythagorean theorem
CD^2 + DE^2 = CE^2
CD^2 + 5^2 = 10^2
CD^2 + 25 =100
Subtract 25 from each side
CD^2 + 25-25 =100-25
CD^2 = 75
Take the square of each side
sqrt(CD^2 ) = sqrt( 75)
BC = 8.660254038
BD = BC +CD
= 6.92820323 + 8.660254038
15.58845727
Answer: $14.85
Step-by-step explanation:
9514 1404 393
Answer:
$2.50
Step-by-step explanation:
The question asks for the total cost of a notebook and pen together. We don't need to find their individual costs in order to answer the question.
Sometimes we get bored solving systems of equations in the usual ways. For this question, let's try this.
The first equation has one more notebook than pens. The second equation has 4 more notebooks than pens. If we subtract 4 times the first equation from the second, we should have equal numbers of notebooks and pens.
(8n +4p) -4(3n +2p) = (16.00) -4(6.50)
-4n -4p = -10.00 . . . . . . . . . . . simplify
n + p = -10.00/-4 = 2.50 . . . . divide by the coefficient of (n+p)
The total cost for one notebook and one pen is $2.50.
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<em>Additional comment</em>
The first equation has 1 more notebook than 2 (n+p) combinations, telling us that a notebook costs $6.50 -2(2.50) = $1.50. Then the pen is $2.50 -1.50 = $1.00.
One could solve for the costs of a notebook (n) and a pen (p) individually, then add them together to answer the question. We judge that to be more work.
Answer:
Step-by-step explanation:
3x - 10 = 2x + 30
x - 10 = 30
x = 40
Check the picture below.
if you check your Unit Circle, it'd be there.
