2 years ago

State the excluded value of 60x^3 /12x

Mathematics

1 answer:

Neporo4naja [7]2 years ago

8 0

Answer:

$\frac{60 {x}^{3} }{12x}$

$5 {x}^{2}$

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Find the exact value by using a half angle identity.tan 75°

kramer

The trigonometric function is given as

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$\tan (\frac{150^{\circ}}{2})=\frac{\sin150^{\circ}}{1+cos150^{\circ}}$ $\tan (75^{\circ})=\frac{\frac{1}{2}}{1-\frac{\sqrt[]{3}}{2}}=\frac{\frac{1}{2}}{\frac{2-\sqrt[]{3}}{2}}^{}$ $\tan 75^{\circ}=\frac{1}{2-\sqrt[]{3}}$

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