The normal distribution curve for the problem is shown below
We need to standardise the value X=405.5 by using the formula


We now need to find the probability of z=0.32 by reading the z-table
Note that z-table would give the reading to the left of z-score, so if your aim is to work out the area to the right of a z-score, then you'd need to do:

from the z-table, the reading

gives 0.6255
hence,

The probability that the mean weight for a sample of 40 trout exceeds 405.5 gram is 0.3475 = 34.75%
Answer:
25/12 - pounds more vegetables
Step-by-step explanation:
first we need to put these variables into like terms
36/12 - 3
8/12 - 2/3
3/12 - 1/4
add the last two up and subtract from the first and you get how much you need left over
The total ball in the bag is 4 + 2 = 6 balls. Their are 4 red balls and 2 blue balls.
If they are drawn singly the probability that 2 blue balls are counted can be expressed as follows
Answer: c
Step-by-step explanation:
Hi Kristian
a - 3b = 22
a = b - 2
We need to solve a = b -2 for a
First, we need to substitute b - 2 for a in a - 3b = 22
a - 3b = 22
b - 2 - 3b = 22
-2b - 2 = 22
-2b = 22 + 2
-2b = 24
b = 24/-2
b = -12
Now substitute -12 for b in a = b - 2
a = b -2
a= -12 - 2
a= -14
Thus, the solution is a = -14 and b = -12
The correct option is the last one (-14,-12)
If you have questions about my answer, please let me know.
Good luck!