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4 years ago

What is the best way to start with code?

Computers and Technology

2 answers:

Butoxors [25]4 years ago

7 0

Answer:

Try out some online courses.

Explanation:

Ksenya-84 [330]4 years ago

3 0

Although coding is relatively easy to learn compared to a lot of other technical skills, it is still something that scares people. At first glance, it may seem complicated, confusing, and very, very hard to master. I mean, how do you go about learning how to code a website if you have no programming experience whatsoever?

The answer is simple – you follow our step by step guide to learning how to code for beginners! By the end of this guide, you should have a clear understanding of the steps that are required if you want to become a programmer, along with the things that you can do to help fast-track your journey.

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A ______ connection provides fast internet service and the ability to exchange large files.

Degger [83]

Answer:

broadband

Explanation:

A broadband connection provides fast internet service and the ability to exchange large files.

3 0

4 years ago

Terri needs to insert a cover page into her document. Where should she go to access the commands to do so? Insert tab, Objects g

dexar [7]

Answer:

Insert tab, Pages group

Explanation:

It just be like dat

7 0

2 years ago

Suppose that a 64MB system memory is built from 64 1MB RAM chips. How many address lines are needed to select one of the memory

alexdok [17]

Answer:

6 address lines

Explanation:

The computation of the number of address lines needed is shown below:

Given that

Total memory = 64MB

= $2^6MB$

= $2^{26} bytes$

Also we know that in 1MB RAM the number of chips is 6

So, the number of address lines is $2^{26} address$ i..e 26 address lines

And, the size of one chip is equivalent to 1 MB i.e. $2^{20} bytes$

For a single 1MB chips of RAM, the number of address lines is

$\frac{2^{26}}{2^{20}} \\\\= 2^6 address$

Therefore 6 address lines needed

5 0

3 years ago

The class at the top of exception class hierarchy is ..........................

Lynna [10]

Answer:

B) Throwable

Explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

There are a wide range of classes on the exception class hierarchy. All the way on the top is the Objects Class but since that is not an available answer we will move on to the next one. The next one is the Throwable class. therefore that is the answer.

**Exception is after Throwable , and Arithmetic Exception is at the bottom.... everything is a class so that is not a part of the hierarchy **

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

6 0

4 years ago

5)What are the differences in the function calls between the four member functions of the Shape class below?void Shape::member(S

Stells [14]

Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. const keyword restricts us so we cannot make any change to s1 or s2 object as well as the Shape function itself.

5 0

3 years ago