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aksik [14]
3 years ago
13

A triangle is inscribed in a rectangle as shown below what is the area of the shaped region

Mathematics
1 answer:
alekssr [168]3 years ago
6 0

Answer:

Step-by-step explanation:

area of rectangle=11×5=55 cm²

area of triangle=1/2×5×3=15/2=7.5 cm²

area of shaded region=55-7.5=47.5 cm²

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BigorU [14]
1) 4c*2
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3 years ago
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Determine if the solution set for the system of equations shown is the empty set, contains one point or is infinite. 5x+7=2y and
Luda [366]

Answer:

The correct option is option B. It has one solution, and it's x=-3

Step-by-step explanation:

We have the following system of equations:

5x+7 = 2y                        (1)

y-9x=23                            (2)

Step 1: Solve for 'y' in equation (2):

y-9x = 23

y = 9x + 23

Step 2: Substitute in equation (1):

5x + 7 = 2y

5x + 7 = 2(9x + 23)

5x + 7 = 18x + 46

Step 3: Solve for x:

7 - 46 = 18x - 5x

-39 = 13x

x= -3

So the correct option is option B. It has one solution, and it's x=-3

7 0
3 years ago
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PLS HELP ASAP ILL GIVE BRAINLKEST THANKS
pshichka [43]

Answer:

C

Step-by-step explanation:

y = 10

x = 8

The y intercept is 0 and the line runs through (0,0)

m = y / x This formula can only be used when the y incept is 0.

m = 10/8

m = 5/4

Equation

y = 5/4 x

3

8 0
2 years ago
HELP MEEEEEE ;-; PLEASE WORTH 20 POINTS
anastassius [24]
This is a right triangle
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2 years ago
At a 20th high school reunion, all the classmates were asked the number of children they had. The probability of having a partic
finlep [7]

Answer:

a) We need to check two conditions:

1) \sum_{i=1}^n P_i = 1

0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1

2) P_i \geq 0 , \forall i=1,2,...,n

So we satisfy the two conditions so then we have a probability distribution

b) P(C \geq 1)

And we can use the complement rule and we got:

P(C \geq 1)= 1-P(C

c) P(C=0) = 0.05

d) For this case we see that the result from part b use the probability calculated from part c using the complement rule.

Step-by-step explanation:

For this case we have the following probability distribution given:

C    0        1        2         3       4       5        6       7        8      

P  0.05   0.14   0.34   0.24  0.11  0.07  0.02  0.02  0.01

And we assume the following questions:

a) Verify that this is a probability distribution

We need to check two conditions:

1) \sum_{i=1}^n P_i = 1

0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1

2) P_i \geq 0 , \forall i=1,2,...,n

So we satisfy the two conditions so then we have a probability distribution

b) What is the probability one randonmly chosen classmate has at least one child

For this case we want this probability:

P(C \geq 1)

And we can use the complement rule and we got:

P(C \geq 1)= 1-P(C

c) What is the probability one randonmly chosen classmate has no children

For this case we want this probability:

P(C=0) = 0.05

d) Look at the answers for parts b and c and explain their relationship

For this case we see that the result from part b use the probability calculated from part c using the complement rule.

5 0
3 years ago
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