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Mrac [35]
2 years ago
8

17. Classify Each Angle Pair then find the value of X

Mathematics
1 answer:
IRISSAK [1]2 years ago
4 0

<u>Given</u> -

  • If l || m, m∠1 = (13x + 24)°, and m∠2 = (5x-6)°,

<u>To find</u> -

  • m∠2.

<u>Concept</u> -

Whenever two parallel lines are cut by a transversal, an interesting relationship exists between the two interior angles on the same side of the transversal. These two interior angles are supplementary angles. Hence, according to the figure l and m are two parallel lines and t is the transversal intersecting them then ∠1 + ∠2 = 180°.

<u>Solution</u> -

\rightarrow\sf{(13x+24)^{ \circ}+(5x-6)^{ \circ}=180^{ \circ}}

\rightarrow\sf{13x+5x+24-6=180}

\rightarrow\sf{18x+18=180}

\rightarrow\sf{18x+18=180}

\rightarrow\sf{18(x+1)=180}

\rightarrow\sf{x+1=\frac{180}{18}}

\rightarrow\sf{x+1=10}

\rightarrow\sf{x=10-1}

\rightarrow\boxed{\bf{x=9}}

m∠2 = (5x-6)° = {5(9) - 6}° = {45 - 6}°= 39°

Henceforth, m∠2 = 39°

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(1) Possible roots

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\text{Possible rational root} = \dfrac{ p }{ q } = \dfrac{\text{factor of constant term}}{\text{factor of leading coefficient}}

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\text{Possible roots are } \large \boxed{\mathbf{x = \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10}}

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\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}

So, x = -2 is a root, and the quotient is 2x² + 2x - 5.

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2x² + 2x - 5 = 0

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