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N76 [4]
2 years ago
7

Cultures of a bacterial species were incubated on the shelf of a refrigerator, out on a lab bench top, on the shelf of a 37°C in

cubator and on the shelf of a 50°C incubator. After incubation, there was no growth at 37°C and 50°C, slight growth out on the bench top and abundant growth at refrigeration. What term could be used for this species?
A. Halophile
B. Mesophile
C. Anaerobe
D. Psychrophile
E. Capnophile
Biology
1 answer:
Oksana_A [137]2 years ago
7 0

Answer:

D. Psychrophile

Explanation:

Psychrophiles or cryophiles are a type of extremophiles i.e. they live in extreme environment. They grow well in low temperatures ranging from -20 to +10 degree Celsius.

Here, the bacteria was incubated at different temperatures. It did not show growth at standard incubation temperature of 37°C which indicates that it might be an extremophile preferring either very hot or very cold environment. But it also did not show growth at 50°C which means that it does not survive well at high temperature.

Lab bench top has generally colder surface compared to the surrounding environment and a little growth was observed there which indicates that this bacteria might require cold temperature for growth. The result was finally confirmed with abundant growth observed inside refrigerator which is only possible if it is a psychrophile.

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Nitrogen is changed into which substances before being used by living things
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Which of these is a food web based on the relationships described above? ​
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2 years ago
Which of the following samples will have the greatest volume at STP?a. 22 g Neb. 22 g Hec. 22 g O2d. 22 g Cl2 e. All have the sa
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Volume of gas at STP is given as :

Volume occupied(dm³) = number of moles x 22.4dm³mol⁻¹

In order to solve this given problem, we would first find the number of moles from the different masses of atoms and molecules given.

Number of moles = \frac{mass }{Molar mass}

Now, let us obtain the molar mass of the given atoms and elements:

For Ne; molar mass is the atomic mass = 20gmol⁻¹

      He = 4gmol⁻¹

      O₂ = (16 x2)gmol⁻¹  = 32gmol⁻¹

      Cl₂ = (35.5x2)gmol⁻¹ = 71gmol⁻¹

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Volume occupied by He at STP = 5.5 x 22.4 = 123.2dm³

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2 years ago
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