All categories

3 years ago

Planet Distance from sun (in km) Distance in scientific notation

Mathematics

1 answer:

Westkost [7]3 years ago

6 0

Answer:

1.5.7909 2. 6.724 3. 9.296 4. 1.416 5. 4.838 6. 1.784 7. 2.793 8. 2.793

Step-by-step explanation: these are the planets in order hope this helps

You might be interested in

I need help................

FrozenT [24]

Answer:

a) $( $\frac{7200}{m}$ )

b) $(20m + 7080 - 43200/m)

d) m= 36 or m= -60

e) $200

Step-by-step explanation:

Please see the attached pictures for full solution.

4 0

3 years ago

Can someone help me with this question ?

kramer

The correct answer is 8 feet tall

3 0

3 years ago

Read 2 more answers

Which of the following represents an arithmetic sequence?

kicyunya [14]

Answer:

5=3+2

7=5+2

9=7+2

so this is 3,5,7,9

Step-by-step explanation:

6 0

3 years ago

Please help me solve this problem ASAP

DiKsa [7]

$\bold{\huge{\blue{\underline{ Solution }}}}$

<h3>Given :-</h3>

The right angled below is formed by 3 squares A, B and C
The area of square B has an area of 144 inches ²
The area of square C has an of 169 inches ²

We have to find the area of square A?

<h3>Let's Begin :- </h3>

The right angled triangle is formed by 3 squares

We have, 

Area of square B is 144 inches²
Area of square C is 169 inches²

We know that,

$\bold{ Area \: of \: square = Side × Side }$

Let the side of square B be x

Subsitute the required values,

$\sf{ 144 = x × x }$

$\sf{ 144 = x² }$

$\sf{ x = √144}$

$\bold{\red{ x = 12\: inches }}$

Thus, The dimension of square B is 12 inches

Area of square C = 169 inches

Let the side of square C be y

Subsitute the required values,

$\sf{ 169 = y × y }$

$\sf{ 169 = y² }$

$\sf{ y = √169}$

$\bold{\green{ y = 13\: inches }}$

Thus, The dimension of square C is 13 inches.

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3>Therefore, By using Pythagoras theorem, </h3>

The sum of squares of base and perpendicular height equal to the square of hypotenuse

That is,

$\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}$

Here, 

Base = x = 12 inches
Perpendicular = z
Hypotenuse = y = 13 inches

Subsitute the required values,

$\sf{ (z)² + (x)² = (y)² }$

$\sf{ (z)² + (12)² = (169)² }$

$\sf{ (z)² + 144 = 169}$

$\sf{ (z)² = 169 - 144 }$

$\sf{ (z)² = 25}$

$\bold{\blue{ z = 5 }}$

Thus, The dimensions of square A is 5 inches

<h3>Therefore,</h3>

Area of square

$\sf{ = Side × Side }$

$\sf{ = 5 × 5 }$

$\bold{\orange{ = 25\: inches }}$

Hence, The area of square A is 25 inches.

6 0

3 years ago

Are (99 – 11 + 10g) - (12 - 119 + 13) and -3(-10g + 12) equivalent expressions? Explain.

Crank

Answer:

)99-11+10g -12+119 -13= 182+10g

)30g-36

Step-by-step explanation:

5 0

3 years ago