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Sergeu [11.5K]
3 years ago
5

Are (99 – 11 + 10g) - (12 - 119 + 13) and -3(-10g + 12) equivalent expressions? Explain.

Mathematics
1 answer:
Crank3 years ago
5 0

Answer:

)99-11+10g -12+119 -13= 182+10g

)30g-36

Step-by-step explanation:

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A survey of 90 men found that an average amount spent on St. Patrick's day of $55 with a standard deviation of $18. A similar su
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Answer:

The value of the test statistic is 4.70.

Step-by-step explanation:

The hypothesis for this test can be defined as follows:

<em>H</em>₀: Men do not spend more than women on St. Patrick's day, i.e. μ₁ = μ₂.

<em>H</em>ₐ: Men spend more than women on St. Patrick's day, i.e. μ₁ > μ₂.

The population standard deviations are not known.

So a <em>t</em>-distribution will be used to perform the test.

The test statistic for the test of difference between mean is:

t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }

Given:

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Compute the value of the test statistic as follows:

t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }=\frac{55-44}{\sqrt{\frac{15^{2}}{90}+\frac{16^{2}}{86} }}=4.70

Thus, the value of the test statistic is 4.70.

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