There are 750 spectators in the stadium of which 420 of them are woman and the rest are man what percent are men
2 answers:
There are 750 spectators in the stadium. 420 of these spectators are women and the rest are men. What percent of the spectators are men.
The fraction represents the number of women in the stadium out of all the 750 people in the stadium. We can subtract 420 from 750 and we will get a difference of 330. Now we know that there are 330 men in the stadium.
The fraction represents the number of men at the stadium out of everyone. To find the percent of men at the stadium, we need to turn
into a percent.
reduced is
because we are dividing both the numerator and denominator by the Greatest Common Factor of 330 and 750 using 30.
11 ÷ 25 = 0.44
0.44 × 100 = 44%
Therefore, 44% of the spectators in the stadium are men.
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Answer:
a) For Pawnee:
Range = 11, Mean = 3.13, Mean deviation = 2.44
For Chickpee:
Range = 7, Mean = 4.25, Mean deviation = 1.59
b) Pawnee Location has fewer lost days.
c) variation of the Chickpee is less than Pawnee location
Step-by-step explanation:
Data given:
For Pawnee:
3 1 0 0 2 11 5 3
Max = 11
Min = 0
Range = Max - Min
Range = 11-0 = 11
Range = 11
For Chickpee:
3 6 8 4 4 5 3 1
Max = 8
Min = 1
Range = Max - Min
Range = 8 - 1
Range = 7
For mean of Pawnee:
Mean = (3 + 1 + 0 + 0 + 2 + 11 + 5 + 3)/8
Mean = 25/8
Mean = 3.125
For mean deviation, we find the difference from the mean of each point.
Note: all the negative values will be taken as 0.
Differences from the mean of each point =
(3-3.13)=0.13, (1-3.31) = 2.13 ,
(0-3.13)=0, (0-3.13)=3.13,
(2-3.13)=1.13, (11-3.13)=7.87,
(5-3.13)=1.87, (3-3.13)=0.13
So, our differences are:
(0.13, 2.13, 0, 3.13, 1.13, 7.87, 1.87, 0.13 )
Mean deviation = Sum of all differences/8
Mean deviation = (0.13+2.13+3.13+3.13+ 1.13+ 7.87+ 1.87+ 0.13)/8
Mean deviation = 2.44
For mean of Chickpee:
Mean = (3+6+8+4+4+5+3+1)/8
Mean = 34/8
Mean = 4.25
Similarly, we need to find mean deviation for Chickpee, for that we need to find the differences first as done above for Pawnee.
Note: all the negative values will be taken as 0
Differences from the mean:
(3-4.25) = 1.25, (6-4.25) =1.75,
(8-4.25) = 3.75, (4-4.25)=0.25,
(4-4.25)=0.25, (5-4.25)= 0.75,
(3-4.25)=1.25, (1-4.25) =3.25
So, the differences are:
Differences = (1.25,1.75,3.75,0.25,0.25,0.75,1.25,3.25)
Mean deviation = (1.25+ 1.75+ 3.75+ 0.25+ 0.25+ 0.75+ 1.25+ 3.25)/8
Mean deviation = 1.59
b) which location has fewer lost days:
This can be found out by the total number of days of Pawnee and chickpee.
Pawnee = Sum of values = (3 + 1 + 0 + 0 + 2 + 11 + 5 + 3) = 25 days
Chickpee = Sum of values = (3+6+8+4+4+5+3+1) = 34 days
Hence, Pawnee Location has fewer lost days.
C) which location has less variation?
Formula for variation = ∑() - (
)
where x = values of the set.
For Pawnee:
=
= 9.8
Sum of square of all the data points of Pawnee = 169
Variation = 169/8 - 98 = 11.325
Similarly,
For Chickpee:
=
= 18.06
Sum of square of all the data points of Chickpee = 176
Variation = 176/8 - 18.06
Variation = 22-18.06
Variation = 4
Hence, variation of the Chickpee is less than Pawnee location