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3 years ago

There are 750 spectators in the stadium of which 420 of them are woman and the rest are man what percent are men

Mathematics

2 answers:

MrMuchimi3 years ago

5 0

44% of people are men

jasenka [17]3 years ago

3 0

There are 750 spectators in the stadium. 420 of these spectators are women and the rest are men. What percent of the spectators are men.

The fraction $\frac{420}{750}$ represents the number of women in the stadium out of all the 750 people in the stadium. We can subtract 420 from 750 and we will get a difference of 330. Now we know that there are 330 men in the stadium.

The fraction $\frac{330}{750}$ represents the number of men at the stadium out of everyone. To find the percent of men at the stadium, we need to turn $\frac{330}{750}$ into a percent. $\frac{330}{750}$ reduced is $\frac{11}{25}$ because we are dividing both the numerator and denominator by the Greatest Common Factor of 330 and 750 using 30.

11 ÷ 25 = 0.44

0.44 × 100 = 44%

Therefore, 44% of the spectators in the stadium are men.

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A bike wheel. The weight of a full steel bead tire is approximately 800 grams, while a lighter wheel weighs only 700 grams. What

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Answer:

a. 800 grams = 1.76 pounds

b. 700 grams = 1.54 pounds

Step-by-step explanation:

Here is a weight conversion problem.

In this question, we shall be making conversions from grams to pounds.

Kindly note that 453.592 grams = 1 pound as stated in the question

a. 800 grams

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800 grams = x pound

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3 years ago

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Which of the following shows the extraneous solution to the logarithmic equation? log Subscript 4 Baseline (x) + log Subscript 4

vekshin1

Given:

The given equation is $\log _{4}(x)+\log _{4}(x-3)=\log _{4}(-7 x+21)$

We need to determine the extraneous solution of the equation.

Solving the equation:

To determine the extraneous solution, we shall first solve the given equation.

Applying the log rule $\log _{c}(a)+\log _{c}(b)=\log _{c}(a b)$ , we get;

$\log _{4}(x(x-3))=\log _{4}(-7 x+21)$

Again applying the log rule, if $\log _{b}(f(x))=\log _{b}(g(x))$ then $f(x)=g(x)$

Thus, we have;

$x(x-3)=-7 x+21$

Simplifying the equation, we get;

$x^2-3x=-7 x+21$

$x^2+4x=21$

$x^2+4x-21=0$

Factoring the equation, we get;

$(x-3)(x+7)=0$

Thus, the solutions are $x=3, x=-7$

Extraneous solutions:

The extraneous solutions are the solutions that does not work in the original equation.

Now, to determine the extraneous solution, let us substitute x = 3 and x = -7 in the original equation.

Thus, we get;

$\log _{4}(3)+\log _{4}(3-3)=\log _{4}(-7 \cdot 3+21)$

$\log _{4}(3)+\log _{4}(0)=\log _{4}(0)$

Since, we know that $\log _{a}(0)$ is undefined.

Thus, we get;

Undefined = Undefined

This is false.

Thus, the solution x = 3 does not work in the original equation.

Hence, x = 3 is an extraneous solution.

Similarly, substituting x = -7, in the original equation. Thus, we get;

$\log _{4}(-7)+\log _{4}(-7-3)=\log _{4}(-7(-7)+21)$

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$\log _{4}(-7)+\log _{4}(-10)=\log _{4}(70)$

Simplifying, we get;

Undefined = $\log _{4}(70)$

Undefined = 3.06

This is false.

Thus, the solution x = -7 does not work in the original solution.

Hence, x = -7 is an extraneous solution.

Therefore, the extraneous solutions are x = 3 and x = -7

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