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3 years ago

X^2 - 11x = 0 solve equation by factoring is there a solution or not?

Mathematics

1 answer:

Kay [80]3 years ago

3 0

First you can take a x out of the whole equation:

x(x-11)=0

Then solve for the solutions:

x=0, 11

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Let mu denote the true average number of minutes of a television commercial. Suppose the hypothesis H0: mu = 2.1 versus Ha: mu &

natka813 [3]

Answer:

A. T > 2.539

Step-by-step explanation:

We have a hypothesis test of the mean, with unknown population standard deviation.

The hypothesis are:

$H_0: \mu = 2.1 \\\\H_a: \mu > 2.1$

From the hypothesis we can see that the test is right-tailed, so the critical value of t should be a positive value.

The degrees of freedom can be calculated as:

$df=n-1=20-1=19$

The significance level is 0.01, so the critical value tc should be the one that satisfies:

$P(t>t_c)=0.01$

Looking up in a t-table, for 19 degrees of freedom, this critical value is tc=2.539.

7 0

3 years ago

Solve the equation

motikmotik

Answer:

Step-by-step explanation:

$\frac{1}{2}$ (2x + 2) - $\frac{1}{4}$ (3x - 1) = 15

multiply through by 4 ( the LCM of 2 and 4 ) to clear the fractions

2(2x + 2) - (3x - 1) = 60 ← distribute parenthesis and simplify left side

4x + 4 - 3x + 1 = 60

x + 5 = 60 ( subtract 5 from both sides )

x = 55

3 0

2 years ago

I still remember, third of December, me in your sweater

DochEvi [55]

Answer:

I love that song!

5 0

3 years ago

Please help.

kondor19780726 [428]

Answer :

27.5 minutes

Steps:

1) put into fraction form:

160/20 = 220/x

2) simplify:

160/20 = 8/1

3) cross multiply:

8 • x = 8x

220 • 1 = 220

4) divide on both sides:

8/8 = crosses out

220/8 = 27.5

6 0

3 years ago

Elimination method: ax+by=r, -bx+cy=s

Alex17521 [72]

$\left[\begin{array}{ccc}ax+by=r\\\\-bx+cy=s\end{array}\right]$

Isolate x for $ax+by=r$

$x= \frac{r-by}{a} ; a \neq 0$

Subsititute $x= \frac{r-by}{a}$

$-b \frac{r-by}{a} +cy=s$

Isolate r for : $-b \frac{r-by}{a}+cy=s$

$r=- \frac{as-acy-b^2y}{b} ; a \neq 0;b \neq 0$

For x : $\frac{r-by}{a}$

Subsititute r = $- \frac{as-acy-b^2y}{b}$

$x= -\frac{as-acy-b^2y}{b}/a$

$x = \frac{cy-s}{b}$

The solutions to the system of equations are:

$r= -\frac{as-acy-b^2y}{b}$ and <span> $x = \frac{cy-s}{b}$
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hope this helps!

3 0

3 years ago