Answer:
concentration targeting strategy
Explanation:
Based on the information provided within the question it can be said that Tennot Inc. most likely uses a concentration targeting strategy. This is a type of strategy in which the company focuses a single specific market segment to put all their efforts into. Which in this scenario Tennot is focusing on the old car market segment and targeting low income customers with these cars.
Answer:
Dr Retained earnings $8.2
Cr Inventory $8.2
Explanation:
By changing method of an inventory valuation, the company should apply it retrospectively based on IAS 8 guidelines on change in accounting estimates and errors. Thus, the said difference from FIFO method to Weighted Average method of valuation should be credited directly against Retained earnings account because, accounts are already closed right after the year ended.
$32-$23.8= $8.2 million
To record the said adjustment you have to
Debit Retained earnings and credit Inventory in the amount of $8.2 million.
Answer
The answer and procedures of the exercise are attached in a microsoft excel document.
Explanation
Please consider the data provided by the exercise. If you have any question please write me back. All the exercises are solved in a single sheet with the formulas indications.
Bank-B is better to invest because it has higher Future value due to higher effective annual interest rate.
Answer:
a) H0: u = presence of a unit root
HA: u ≠ presence of a unit root ( i.e. stationary series )
b) t stat = -0.064
c) We will reject the Null hypothesis and the next step will be to accept the alternative hypothesis
d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise
Explanation:
<u>a) stating the null and alternative hypothesis</u>
H0: u = presence of a unit root
HA: u ≠ presence of a unit root ( i.e. stationary series )
<u>b) performing the test </u>
critical value = -2.88
T stat = coefficient / std error
= -0.02 / 0.31 = -0.064
c) From the test, the value of T stat > critical value we will reject the Null hypothesis hence the next step will be to accept the alternative hypothesis
d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise
