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morpeh [17]
3 years ago
6

Greg is training for the upcoming basketball season. His schedule this week allows him to complete at most 8 training sessions.

When Greg trains, he either spends 45 minutes on skills or 35 minutes on conditioning. To avoid excess fatigue, his coach requires Greg to spend no more than 360 minutes training in any week.
Which system of inequalities can be used to determine the time spent on skills, x, and the time spent on conditioning, y, that Greg can complete this week?
Mathematics
2 answers:
slamgirl [31]3 years ago
8 0

Answer:

A

Step-by-step explanation:

Sav [38]3 years ago
3 0

Answer:

\left\{\begin{array}{l}x+y\le360\\ \\\dfrac{x}{45}+\dfrac{y}{35}\le 8\end{array}\right..

Step-by-step explanation:

Let x minutes be the time spent on skills and y minutes be the time spent on conditioning that Greg can complete this week.

1. To avoid excess fatigue, his coach requires Greg to spend no more than 360 minutes training in any week, then

x+y\le 360.

2. When Greg trains, he either spends 45 minutes on skills or 35 minutes on conditioning. If Greg spends x minutes on skills, then \dfrac{x}{45} is the number of skills training sessions. If Greg spends y minutes on conditioning, then \dfrac{y}{35} is the number of conditioning training sessions. His schedule this week allows him to complete at most 8 training sessions, then

\dfrac{x}{45}+\dfrac{y}{35}\le 8.

Therefore, the following system of inequalities can be used to determine the time spent on skills, x, and the time spent on conditioning, y, that Greg can complete this week

\left\{\begin{array}{l}x+y\le360\\ \\\dfrac{x}{45}+\dfrac{y}{35}\le 8\end{array}\right..

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timama [110]

Answer:

c. The number of 7's in a randomly selected set of five random digits from a table of random digits.

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Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n, p)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

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The conditions to apply this distribution is that we have the parameters fixed n and p.

Let's analyze one by one the possible solutions:

a. The number of traffic tickets written by each police officer in a large city during one month.

False, the number of traffic tickets written by each police is not a fixed amount always, so then the value of n change and we can't apply a binomial model for this case.

b. The number of hearts in a hand of five cards dealt from a standard deck of 52 cards that has been thoroughly shuffled.

False, not all the hands of size 5 are equal and since we can't ensure this condition then the binomial model not apply for this case

c. The number of 7's in a randomly selected set of five random digits from a table of random digits.

True, for this case we have a value fixed for n =5 and the probability is defined for each number 1/10 so then the random variable "The number of 7's in a randomly selected set of five random digits" can be modelled with the binomial probability function.

d. The number of phone calls received in a one-hour period.

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e. All of the above.

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SashulF [63]

Answer:

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Answer:

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