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Svetach [21]
4 years ago
11

How do you solve cos((π/6)x)=0

Mathematics
1 answer:
zlopas [31]4 years ago
7 0
\bf cos\left( \frac{\pi }{6}x \right)=0\implies cos^{-1}\left[ cos\left( \frac{\pi }{6}x \right) \right]=cos^{-1}(0)
\\\\\\
\cfrac{\pi x}{6}=cos^{-1}(0)\implies \cfrac{\pi x}{6}=
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}\\\\
-------------------------------

\bf \cfrac{\pi x}{6}=\cfrac{\pi }{2}\implies \pi x=\cfrac{6\pi }{2}\implies x=\cfrac{6\pi }{2\pi }
\implies \measuredangle x=\stackrel{radians}{3}\\\\
-------------------------------\\\\
\cfrac{\pi x}{6}=\cfrac{3\pi }{2}\implies\pi x=\cfrac{18\pi }{2}\implies x=\cfrac{18\pi }{2\pi }\implies \measuredangle x=\stackrel{radians}{9}
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GarryVolchara [31]

Answer: n = 4π(sq)q/(t(sq)*p)

Step-by-step explanation: please see attachment for clearer details. Thanks!

5 0
3 years ago
How do you wirte 7.632 in two other forms
Alenkinab [10]

Answer:

763.2% or 954/125

Step-by-step explanation:


5 0
4 years ago
X<br> 8<br> 17<br> Find the exact value of x.<br> X=
Furkat [3]

Answer:

621

629

Step-by-step explanation:

We know that

sin

(

x

+

y

)

=

sin

x

cos

y

+

sin

y

cos

x

If

cos

x

=

8

17

and

sin

y

=

12

37

We can use,

cos

2

x

+

sin

2

x

=

1

and

cos

2

y

+

sin

2

y

=

1

To calculate

sin

x

and

cos

y

sin

2

x

=

1

−

cos

2

x

=

1

−

(

8

17

)

2

=

225

17

2

sin

x

=

15

17

cos

2

y

=

1

−

sin

2

y

=

1

−

(

12

37

)

2

=

1225

37

2

cos

y

=

35

37

so,

sin

(

x

+

y

)

=

15

17

⋅

35

37

+

12

37

⋅

8

17

=

621

629

Answer link

Shwetank Mauria

Nov 22, 2016

sin

(

x

+

y

)

=

621

629

or

−

429

629

depending on the quadrant in which sine and cosine lie.

Explanation:

Before we commence further, it may be mentioned that as

cos

x

=

8

17

,

x

is in

Q

1

or

Q

4

i.e.

sin

x

could be positive or negative and as

sin

y

=

12

37

,

y

is in

Q

1

or

Q

2

i.e.

cos

y

could be positive or negative.

Hence four combinations for

(

x

+

y

)

are there and for

sin

(

x

+

y

)

=

sin

x

cos

y

+

cos

x

sin

y

, there are four possibilities.

Now as

cos

x

=

8

17

,

sin

x

=

√

1

−

(

8

17

)

2

=

√

1

−

64

289

=

√

225

289

=

±

15

17

and

as

sin

y

=

12

37

,

cos

y

=

√

1

−

(

12

37

)

2

=

√

1

−

144

1369

=

√

1225

1369

=

±

35

37

Hence,

(1) when

x

and

y

are in

Q

1

sin

(

x

+

y

)

=

15

17

×

35

37

+

8

17

×

12

37

=

525

+

96

629

=

621

629

(2) when

x

is in

Q

1

and

y

is in

Q

2

sin

(

x

+

y

)

=

15

17

×

−

35

37

+

8

17

×

12

37

=

−

525

+

96

629

=

−

429

629

(3) when

x

is in

Q

4

and

y

is in

Q

2

sin

(

x

+

y

)

=

−

15

17

×

−

35

37

+

8

17

×

12

37

=

525

+

96

629

=

621

629

(4) when

x

is in

Q

4

and

y

is in

Q

1

sin

(

x

+

y

)

=

−

15

17

×

35

37

+

8

17

×

12

37

=

−

525

+

96

629

=

−

429

629

Hence,

sin

(

x

+

y

)

=

621

629

or

−

429

629

7 0
3 years ago
A bird descends at the rate of 10 ft/min. How long will it
MakcuM [25]

Answer:

30 minutes

Step-by-step explanation:

300/10= 30

Hope this helps! :)

8 0
3 years ago
Read 2 more answers
Is this angle side angle, angle angle side, or not congruent.​
KatRina [158]
<h3>Answer: C) Not congruent</h3>

We have 2 pairs of congruent angles, so we can prove the triangles are similar triangles (using the AA similarity theorem). But we don't have enough information to prove them to be congruent. We would need at least one pair of sides to be congruent so we could use either AAS or ASA.

For instance, if we knew that AT = AP, then we would use AAS. If we knew that HT = MP, then we would use ASA instead. However, we don't have either bit of information like this. The triangles may or may not be congruent. We simply don't have enough information to say either way. We can't definitively say they are congruent, so we just lean toward "not congruent".

3 0
3 years ago
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