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3 years ago

15

- tan²x + sec^2x = 1 make the left hand side match the right side

1 answer:

natta225 [31]3 years ago

5 0

u can check below the line

Not the upper portion

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Help please ! whoever answers correctly gets brainliest :)

musickatia [10]

Answer:

1: proportional

2: non-proportional

3: non-proportional

4: non-proportional

5: proportional

6: proportional

7: non-proportional

8: proportional

9. proportional.

10. proportional.

11. non-proportional.

12. proportional.

Step-by-step explanation:

I'm unsure how the proportional ones are actually calculated depending if it requires a dot on the exact origin, but depending on what I can graphically view and assume; every graph with the line running through the origin is proportional and every graph where the line does not run through the origin is non-proportional.

7 0

3 years ago

Read 2 more answers

Can anyone do 4,5 and 6 for me plz

cricket20 [7]

For question 4, $sinA =\frac{a}{c}, cosA= \frac{b}{c}, tan B = \frac{b}{a}, sin J = \frac{j}{l}, cosK = \frac{j}{l}, tanK = \frac{k}{j}.$

Question 5. Option a and question 6. Option j

Step-by-step explanation:

Step 1:

The three basic formula needed to solve these questions are:

$sin\theta = \frac{oppositeside}{hypotenuse} , cos\theta = \frac{adjacentside}{hypotenuse}, tan\theta= \frac{opposite side}{adjacent side}.$

Step 2:

Using the above formula, we solve the following values

$sinA = \frac{oppositeside}{hypotenuse}$ $=\frac{a}{c}.$

$cosA = \frac{adjacentside}{hypotenuse}$ $= \frac{b}{c}.$

$tanB= \frac{opposite side}{adjacent side}$ $= \frac{b}{a}.$

$sinJ = \frac{oppositeside}{hypotenuse}$ $= \frac{j}{l}.$

$cosK = \frac{adjacentside}{hypotenuse}$ $= \frac{j}{l}.$

$tanK= \frac{opposite side}{adjacent side}$ $= \frac{k}{j}.$

Step 3:

For question 5, The triangle's angle = 23°, opposite side = BC inches and hypotenuse = 4 inches.

$sin\theta= \frac{opposite side}{hypotenuse}. sin 23^{\circ}= \frac{BC}{4}, sin23^{\circ} = 0.3907,BC = (0.3907)(4) = 1.5628.$

SO BC is 1.5628 inches, rounding this off to the nearest tenth, we get BC = 1.6 inches which is option a.

Step 4:

For question 6, The triangle's angle = 50°, opposite side = QR m the adjacent side = 8.1 m.

$tan\theta= \frac{opposite side}{adjacentside}. tan 50^{\circ}=\frac{QR}{8.1}, tan50^{\circ} = 1.1917,QR = (1.1917)(8.1) = 9.65277$

SO QR is 9.65277 meters, rounding this off to the nearest tenth, we get QR = 9.7 inches which is option j.

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3 years ago

What is the value of x in the triangle below? Round your answer to the nearest tenth if necessary. Please show your work! tyy

Tanzania [10]

Answer:

x = 14.3

Step-by-step explanation:

To find one of the sides, we can use the pythagorean theorem:

a² + b² = c²

a² = c² - b²

a = √c² -b²

a = √(20)² -( 14)²

a = 14.3

8 0

3 years ago

A metalworker has a metal alloy that is 25% copper and another alloy that is 65% copper. How many kilograms of each alloy shou

Softa [21]

Not sure if you have learned this way of solving

8 0

4 years ago

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87 3/62 estimated! Worth 13 points!!!! I need the anwser and explanation as soon as possible!!! PLZZZZ

Maksim231197 [3]

What is the math equation

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3 years ago