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Morgarella [4.7K]
3 years ago
14

Jane max and Greg are splitting a 10 ounce bag of popcorn if they show the popcorn equally how many ounces of popcorn will each

person get
Mathematics
1 answer:
NARA [144]3 years ago
7 0
Each person will get 3.33 ounces of popcorn if there are 3 people (Jane,Max, and Greg)
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Derek flips a coin and rolls a number cube at the same time. Derek rolls an even number. Find the probability that the coin came
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Coin: 50%; 1/2 chance to get heads
dice: 17%; 1/6 chance to get 2
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Write a unit rate for the situation. Show all work!
Alexxandr [17]

Answer:

4 goals per hour

Step-by-step explanation:

\frac{goals}{hour}=\frac{12}{3}=\frac{12/3}{12/3}=\frac{4}{1}

The unit rate would be 4 goals per hour.

Hope this helps.

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3 years ago
Please help me im literally crying help if I fail i give up i can't.​
Natasha2012 [34]

Answer:

52 m²

Step-by-step explanation:

12x3 = 36

2 x (11-3) = 2x8 = 16

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A rope 33cm long has a mass of 561g. What is the mass of 13cm of this rope?
Digiron [165]

Answer:

221g

Step-by-step explanation:

561g divided by 33cm is how much 1 cm of rope would be so then you multiply that amount by 13

8 0
4 years ago
It is known that IQ scores form a normal distribution with a mean of 100 and a standard deviation of 15. If a researcher obtains
sdas [7]

Answer:

X \sim N(100,15)  

Where \mu=100 and \sigma=15

We select a sample of n=16 and we are interested on the distribution of \bar X, since the distribution for X is normal then we can conclude that the distribution for \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Because by definition:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

E(\bar X) = \mu

Var(\bar X) = \frac{\sigma^2}{n}

And for this case we have this:

\mu_{\bar X}= \mu = 100

\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

X \sim N(100,15)  

Where \mu=100 and \sigma=15

We select a sample of n=16 and we are interested on the distribution of \bar X, since the distribution for X is normal then we can conclude that the distribution for \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Because by definition:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

E(\bar X) = \mu

Var(\bar X) = \frac{\sigma^2}{n}

And for this case we have this:

\mu_{\bar X}= \mu = 100

\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75

6 0
3 years ago
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