Help somebody thanks .

Julli [10]

Answer:

A

Step-by-step explanation:

since it is <= we know that it is including the possibility of being equal so it is not a dotted line leaving only A and B as options. since its is <= it must be on the as the x increases the y must decrease. so the answer is A.

8 0

2 years ago

How many times would a face card (jack, queen, or king) likely be drawn from the deck in 260 draws?

Tanzania [10]

Answer:

8/10

Step-by-step explanation:

You would divide the cards and so you will get your answer

6 0

2 years ago

Read 2 more answers

Anita has a cellphone contract that costs her R100 per month plus 85 cents per peak time SMS,and 25 cents per off-peak time SMS.

algol [13]

Answer:

Anita's monthly bill will be $164.25.

Step-by-step explanation:

Since Anita has a cellphone contract that costs her R100 per month plus 85 cents per peak time SMS, and 25 cents per off-peak time SMS, if she sends 45 SMSs during peak time and 105 SMSs during off-peak time In a month To determine what will her monthly bill come to, the following calculation must be performed:

100 + (0.85 x 45) + (0.25 x 105) = X

100 + 38.25 + 26.25 = X

138.25 + 26.25 = X

164.25 = X

Therefore, her monthly bill will be $ 164.25.

6 0

2 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

7 months ago

Find the area of the figure.

Contact [7]

area of rectangle= 8*13=104m^2

base of the Triangle= 13 -(4+4)=5

area of Triangle = 5*6/2=15m^2

area of shaded shape =104-15= 89m^2

7 0

2 years ago