What is 7.86 rounded to the nearest tenth

Is (5.7) a solution for the following system of equations? y=2x-3 y=x+2

alukav5142 [94]

Answer: yes y=2x-3, y=x+2 : y=7, x=5

4 0

3 years ago

Help me please numbers 7 and 8

Olegator [25]

7. plot the points and then measure the height and base
then find the area of parallelogram 1/2*b*h
8. draw a horizontal line on any point y axis
and then plot r go to 0 and then up one over one repeat the steps and then down one to the right one

3 0

3 years ago

Write the equation of the line that passes through (-6,0) and is parallel to the line y=5x-43

AVprozaik [17]

The equation of the line that passes through (-6,0) and is parallel to the line y = 5x - 43 in slope intercept is y = 5x + 30

Solution:

Given that line that passes through (-6, 0) and is parallel to the line y = 5x - 43

We have to find the equation of line

Let us first find slope of line having equation y = 5x - 43

The slope intercept form of line is given as:

y = mx + c ------- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing equation of line y = 5x - 43 with slope intercept form y = mx + c,

we get m = 5

Thus slope of given line is 5

We know that slopes of parallel lines are equal

Thus the slope of line parallel to given line is also 5

Now let us find equation of line having slope "5" and passes through (-6, 0)

Substitute m = 5 and (x, y) = (-6, 0) in eqn 1

y = mx + c

0 = 5(-6) + c

Thus the required equation is:

Substitute c = 30 and m = 5 in eqn 1

y = 5x + 30

Thus the required equation of line is found

8 0

3 years ago

Which of the following ratios correctly describes the tangent function? a. opp/adj b. opp/hyp c. adj/hyp

Elena L [17]

A. opp/adj because the the tangent is the hypotenuse so it eliminates all equations that require the hypotenuse.

7 0

3 years ago

Read 2 more answers

What are the minimum, first quartile, median, third quartile, and maximum of the data set? 2, 13, 17, 14, 9, 3, 16, 12

Alex777 [14]

So before anything, rearrange the data so that it's in ascending order: {2,3,9,12,13,14,16,17}

Next, the minimum and maximum are as they seem: the smallest and largest numbers in the data. Looking at our data, 2 is our minimum and 17 is our maximum.

Next, to find the median, find the number that is in the middle of the data set. If there isn't one number in the middle, find the average of the two middle numbers to get your median:

$\{2,3,9,\overbrace{\boxed{12,13,}}^{\textsf{middle numbers}}14,16,17\}\\\\\frac{12+13}{2}\\\\\frac{25}{2}\\\\12.5$

The median is 12.5.

Next, to find the first quartile, or the lower quartile, find the "median" of the numbers to the left of the median.

$\overbrace{\{2,\boxed{3,9,}12,}^{\textsf{left of median}}13,14,16,17\}\\\\\frac{3+9}{2}\\\\\frac{12}{2}\\\\6$

The first quartile is 6.

Next, to find the third quartile, or the upper quartile, find the "median" of the numbers to the right of the median.

$\{2,3,9,12,\overbrace{13,\boxed{14,16,}17\}}^{\textsf{right of median}}\\\\\frac{14+16}{2}\\\\\frac{30}{2}\\\\15$

The third quartile is 15.

3 0

3 years ago