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frutty [35]
3 years ago
8

At what value of x does the graph of the following function F(x) have a vertical asymptote? F(x) = 4x/3x-6

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
6 0

Answer:

vertical asymptote at x = 2

Step-by-step explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

3x - 6 = 0 ⇒ x = 2 ← is the vertical asymptote

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