636cm.
This can be found with the Pythagorean Theorem which will give you a side length of 4.5
meters, which rounds to roughly 636cm.
What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41
scZoUnD [109]
The original data set is
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}
Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70}
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median.
The value in the 8th slot is 54, so this is the median
Divide the sorted data set into two lists. I'll call them L and U
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).
Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value.
Therefore, Q3 = 62
Answer: 62</span>
LCD would be 18
8/9 = 16/18
2/3 = 12/18
1/9 = 2/18
Answer: 
.
Step-by-step explanation:
It is given that Point A is at (-5, -4) and point B at (-3, 3).
We need to find the coordinates of the point which is 3/4 of the way from A to B.
Let the required point be P.
It means, point P divides segment AB in 3:1.
Section formula: If a point divides a line segment in m:n, then
Using section formula, we get
Therefore, the required point is .
Answer:
Step-by-step explanation:
∩ 
is asking for the intersection of sets 
and , or simply, which numbers can be found in both sets.
The numbers shared between the two sets are 
.
Next, we need to union this result with the set 
, or simply, combine the numbers in both sets together.
This would result in 
