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Maksim231197 [3]
3 years ago
9

a firefighter dives at 7.5 m/sec from window to net. If window is 34 m above net, what speed does firefighter hit net. ACCELRATI

ON IS 9.8 m/sec^2
Mathematics
1 answer:
lianna [129]3 years ago
5 0

Answer:

Step-by-step explanation:

This is more physics than math, but since "The book of nature is written in the language of mathematics"...

Anyway, the one-dimesional motion equation you want to use here resembles the quadratic we use to model parabolic motion. It is

v^2=v_0^2+2aΔx

where v is the final velocity of the firefighter, v₀ is the initial velocity of the firefighter, a is -9.8 m/s/s (negative because the motion is in the downward direction), and Δx is -34 m. This is also negative because where the firefighter lands is below the point at which he started. This is important, because if you leave the 34 as positive, you end up with a negative radicand...and that's not gonna work. Filling in the formula:

v^2=(7.5)^2+2(-9.8)(-34)

Paying close attention to significant digits here is important (at least it is when I teach physics in school!). Since there are 2 significant digits in 7.5, we need 2 in the product. 7.5 squared is 56.25 which will round to 56. Then on the right side of the plus sign, we need 2 significant digits as well since the number 2 is part of the equation. We don't count it as significant if it is part of the equation. 2(-9.8)(-34) = 666.4 but that will round to 670. NOW, since the rules for significant digits are different in multiplication and addition, you have to round each first, then take the square root of the sum, rounding at the end. In this case we will round to the place that holds the least significance between the 2 numbers. In our case that is the tens place, since the tens place is less significant than is the 1's place. The number 7 is in the tens place. (Following that rule is super tricky, and also quite maddening!)

What we have here is

v^2=56+670 and

v=\sqrt{56+670}

That leaves us with

v = 26.94438j

But don't forget we round that to the tens place which comes out in the end, finally, to

v = 30 m/s

 

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lawyer [7]

The 5 number summary are

Minimum = 10, Lower quartile = 11, Median = 12, Upper quartile = 17 and Maximum = 19

<h3>How to identify the 5 number summary?</h3>

The complete question is in the attached image

The 5 number summary of box plot are:

  • Minimum
  • Lower quartile
  • Median
  • Upper quartile
  • Maximum

Each of these summaries are represented by the vertical lines of the box plot

From the attached box plot, we have:

Minimum = 10, Lower quartile = 11, Median = 12, Upper quartile = 17 and Maximum = 19

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What is the slope given the following two points (2,-4) and (1, 5)?
VMariaS [17]

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Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Bart used place value and the distributive property to rewrite the expression 6(412). His work is shown below. 6(412) = 6(400 +
egoroff_w [7]

Bart should;

Multiply 6(400), 6(10), and 6(2) ⇒ 2nd

Multiply each addend by 6 ⇒ 4th

Find the sum of (2400 + 60 + 12) ⇒ 5th

Step-by-step explanation:

Let us revise the distributive property

  • a(b + c) = ab + ac
  • a(b + c + d) = ab + ac + ad

Bart used place value and the distributive property to rewrite the

expression 6(412)

His work is shown 6(412) = 6(400 + 10 + 2)

We need to know what Bart should do to find the product

∵ 6(412) = 6(400 + 10 + 2)

- Multiply each number in the bracket by 6 in the right hand side

∴ 6(400 + 10 + 2) = (6)(400) + (6)(10) + 6(2)

∴ 6(400 + 10 + 2) = 2400 + 60 + 12

∴ He should to multiply each addend by 6 and then find the sum of

  (2400 + 60 + 12)

Bart should;

Multiply 6(400), 6(10), and 6(2)

Multiply each addend by 6

Find the sum of (2400 + 60 + 12)

Learn more:

You can learn more about the place value in brainly.com/question/120752

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The point (2,-5) is on the graph of which equation?
elena55 [62]
The answer is A,
if you plug in the points of (2,-5) into
y=x-7
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so the equation is true
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