Answer:
62: 300l/hr
63: .018mi/s
64: .46qt/s
65: 298.2mi/hr
Step-by-step explanation:
62: 5x60=300
63: 68/60=1.13/60=.018
64:7gal=28qt 28/60=.467
65: 8km=4.97mi 4.97x60=298.2
Information about concavity is contained in the second derivative of a function. Given f(x) = ax² + bx + c, we have
f'(x) = 2ax + b
and
f''(x) = 2a
Concavity changes at a function's inflection points, which can occur wherever the second derivative is zero or undefined. In this case, since a ≠ 0, the function's concavity is uniform over its entire domain.
(i) f is concave up when f'' > 0, which occurs when a > 0.
(ii) f is concave down when f'' < 0, and this is the case if a < 0.
In Mathematica, define f by entering
f[x_] := a*x^2 + b*x + c
Then solve for intervals over which the second derivative is positive or negative, respectively, using
Reduce[f''[x] > 0, x]
Reduce[f''[x] < 0, x]
Answer:
3
Step-by-step explanation:
note that zeros and x-intercepts are the same with different names
There are 2 zeros from the quadratic factor and 1 from the linear factor.
To find them equate the function to zero, that is
(x² - x - 2)(3x - 2) = 0
(x - 2)(x + 1)(3x-2) = 0 ← factoring the quadratic
equate each factor to zero and solve for x
x - 2 = 0 ⇒ x = 2
x + 1 = 0 ⇒ x = - 1
3x - 2 = 0 ⇒ x = 
Answer:what are all the choices
Also it’s 0
Step-by-step explanation:
The answer is 39.
do 2x2x3 (answer is 12) then 27+12.
