The answer is D.
The others equal 90
The statement that 99% of all confidence intervals with a 99% confidence level should contain the population parameter of interest is false.
A confidence interval (CI) is essentially a range of estimates for an unknown parameter in frequentist statistics. The most frequent confidence level is 95%, but other levels, such 90% or 99%, are infrequently used for generating confidence intervals.
The confidence level is a measurement of the proportion of long-term associated CIs that include the parameter's true value. This is closely related to the moment-based estimate approach.
In a straightforward illustration, when the population mean is the quantity that needs to be estimated, the sample mean is a straightforward estimate. The population variance can also be calculated using the sample variance. Using the sample mean and the true mean's probability.
Hence we can generally infer that the given statement is false.
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Answer:
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Answer:
The inequality for amount x (in dollars) is given by
x ≤ $33 - (cost of necklace).
Step-by-step explanation:
Let the cost of the necklace be $ y.
The amount for the necklace is constant and it is less than $33 and it is also known that the amount for the necklace will be spent.
Therefore after the necklace has been purchased and the amount deducted from $33 the remaining amount can be used completely or partly to purchase the other item.
Let the cost in dollars of the other item be $x.
The inequality for amount x (in dollars) is given by
x ≤ $33 - (cost of necklace)
It would be A. <span>y = −2x − 4.
Hope this helps!!
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